我正在使用django-nonrel和mongodb来开发app。我知道对象id以对象创建的插入时间的时间戳开始。因此,可以根据_id字段进行时间范围查询。
如何根据python或django中的给定时间生成最小的object_id?
答案 0 :(得分:0)
from bson.objectid import ObjectId
import time
def get_minimal_object_id_for_int_timestamp(int_timestamp=None):
if not int_timestamp:
int_timestamp=int(time.time())
return ObjectId(hex(int(int_timestamp))[2:]+'0000000000000000')
def get_int_timestamp_from_time_string(time_string=None):
# format "YYYY-MM-DD hh:mm:ss" like '2012-01-05 13:01:51'
if not time_string:
return int(time.time())
return int(time.mktime(time.strptime(time_string, '%Y-%m-%d %H:%M:%S')))
def get_minimal_object_id_for_time_string(time_string=None):
return get_minimal_object_id_for_int_timestamp(get_int_timestamp_from_time_string(time_string=time_string))
我终于找到了解决方案。希望它对其他人有所帮助。
答案 1 :(得分:0)
这是OP提供的另一个答案的更加pythonic版本,以及文档:
from bson.objectid import ObjectId
import datetime
def datetime_to_objectid(dt):
# ObjectId is a 12-byte BSON type, constructed using:
# a 4-byte value representing the seconds since the Unix epoch,
# a 3-byte machine identifier,
# a 2-byte process id, and
# a 3-byte counter, starting with a random value.
timestamp = int((dt - datetime.datetime(1970,1,1)).total_seconds())
time_bytes = format(timestamp, 'x') #4 bytes
return ObjectId(time_bytes+'00'*8) #+8 bytes
然而,从pymongo的1.6版开始,执行以下操作会更优雅:
from bson.objectid import ObjectId
ObjectId.from_datetime(dt)