我有3个表,名为
students (id, name)
subjects (id, name, is_published)
student_subjects (id, student_id, subject_id)
学生参加的科目是student_subjects
。但有些情况下student_subjects包含NULL subject_id
学生
以下是Students
表
1;"John"
2;"Ahmeah"
3;"Dina"
4;"Leo"
5;"Lenon"
主题表
1;"Computer Sci";1
2;"Physics";1
3;"Bio";1
4;"Maths";0
Student_subjects
1;1;1
2;1;2
3;1;4
4;2;1
5;2;3
6;2;4
7;3;2
8;4;1
9;5;NULL
目前,为了取得所有学生的科目,并显示没有附加科目的学生的姓名,我使用的查询如下
SELECT
students.*,
inners.name
FROM
students
LEFT JOIN ( SELECT
student_id,
subjects.name
FROM
student_subjects
JOIN subjects ON ( student_subjects.subject_id = subjects.id AND subjects.is_published = 1)
) AS inners ON (inners.student_id = students.id )
是否有更好的方法来执行相同的http://sqlfiddle.com/#!12/9cf93/12
答案 0 :(得分:1)
SELECT s.*, su.name AS SubjName
FROM students AS s
LEFT JOIN student_subjects AS ss ON ss.student_id = s.id
LEFT JOIN subjects AS su ON su.id = ss.subject_id
与您列出的那个相同。这就是你追求的目标吗?