我无法弄清楚如何做到这一点。 我有一个按钮,一旦它被点击,我想在五秒内开始一个过程,当用户在等待我想显示倒计时 - 5,4,3,2,1
我无法让这个工作我尝试过使用nstimer,但这不起作用。 有什么建议? Thankds
答案 0 :(得分:2)
您可以使用dispatch_after()
并利用块捕获范围的方式来跟踪您剩余的秒数。
- (IBAction)buttonHandler:(UIButton *)sender
{
if (self.countingDown)
return;
[self startCountDown];
}
- (void)startCountDown
{
self.countingDown = YES;
self.button.enabled = NO;
int seconds = 5;
[self countDownFor:seconds];
}
- (void)countDownFor:(int)seconds
{
self.countDownLabel.text = [NSString stringWithFormat:@"%d",seconds];
if (seconds == 0) {
self.countingDown = NO;
self.button.enabled = YES;
return;
}
double delayInSeconds = 1.0;
dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, (int64_t)(delayInSeconds * NSEC_PER_SEC));
dispatch_after(popTime, dispatch_get_main_queue(), ^(void){
[self countDownFor:(seconds - 1)];
});
}
答案 1 :(得分:1)
使用GCD和块的优雅解决方案:
__block void (^runBlock)(int) = ^(int i) {
countdownLabel.text = [NSString stringWithFormat:@"%d", i];
if(i>0) {
dispatch_time_t popTime = dispatch_time(DISPATCH_TIME_NOW, 1*NSEC_PER_SEC);
dispatch_after(popTime, dispatch_get_main_queue(), ^(void){
runBlock(i-1);
});
} else {
runBlock = nil; // Breaking retain cycle
// Time to start your great action!
// ...
}
};
runBlock(5);
答案 2 :(得分:0)
尝试类似
的内容[NSTimer scheduledTimerWithTimeInterval:1
target:self
selector:@selector(methodNameUsedToupdateButtonText)
userInfo:nil
repeats:YES];
如果倒计时到达0(并且如果视图卸载)
,则使计时器无效