Question

我有一个看起来像这样的文本文件：

[1] Header information Timestamp Text begins
Text continues
Text continues
Text continues

[2] Header information Timestamp Text begins
Text continues
Text continues

[3] Header information Timestamp Text begins
Text continues
Text continues
Text continues

我想读取该文件，并分别处理每个条目（它们分别是1到20或30行）。

有没有办法使用空行作为分隔符来循环文件？

Answer 1

答案是肯定的！

awk -vRS="" '...'会将空白行视为行拆分器。

拿你的例子并测试：

kent$  cat b.txt
[1] Header information Timestamp Text begins
Text continues
Text continues
Text continues

[2] Header information Timestamp Text begins
Text continues
Text continues

[3] Header information Timestamp Text begins
Text continues
Text continues
Text continues

kent$  awk -vRS="" '{print "==== new block here ===="}1' b.txt  
==== new block here ====
[1] Header information Timestamp Text begins
Text continues
Text continues
Text continues
==== new block here ====
[2] Header information Timestamp Text begins
Text continues
Text continues
==== new block here ====
[3] Header information Timestamp Text begins
Text continues
Text continues
Text continues

Answer 2

这是一个纯粹的bash解决方案：

{
    read -r block    # First line only
    while read -r; do
        if [[ $REPLY =~ ^$ ]]; then
            # Do what you like with the contents 
            # $block here, then ...
            block=""
        else
            block+="$REPLY"
        fi
    done
 } < file.txt

以块为单位而不是逐行读取文件？

2 个答案: