我在尝试将图书附加到课程列表列表时遇到错误。关于为什么或我可以做些什么来修复它的任何想法?
//For each book in a class...
for (int k = 0; k < rows.size(); k++) {
Book book = new Book()
//Assign the values to a new book object
book.id = rows[k].getProperty("ISBN")
book.title = rows[k].getProperty("title")
book.author = rows[k].getProperty("author")
book.required = rows[k].getProperty("required_optional")
book.purchaseType = rows[k].getProperty("rental_purchase")
//book.purchasePrice = rows[k].getProperty("purchase_price")
//book.rentalPrice = rows[k].getProperty("rental_fee")
//Append the book to the books list object in the particular class
classes[i].books[k + 1] << book
}
答案 0 :(得分:1)
而不是[]
使用getAt
进行访问,?
运算符将起作用:
classes?.getAt(i)?.books?.getAt(k+1) << book
或
classes?.getAt(i)?.books[k+1] << book
答案 1 :(得分:0)
没有完整的代码,很难知道会发生什么。试试这段代码,它会显示哪个值为null:
// first check if classes[i] is null, add error handling if it is
if (classes[i]!=null) {
//For each book in a class...
for (int k = 0; k < rows.size(); k++) {
def books = classes[i].books[k + 1]
if (books!=null) {
// you can set values directly here
def row = rows[k]
Book book = new Book(
id: k.getProperty("ISBN"),
title: k.getProperty("title")
// ...
)
//Append the book to the books list object in the particular class
books << book
} else {
println "books is null, do something clever"
}
}
} else {
println "classes[i] is null, do something clever"
}
我没有测试它,你可以用一些时髦的善良来缩短它。这只是为了让你开始
答案 2 :(得分:0)
我不确定'类'是什么,但如果它是一个包含'Book'的列表,你可以做到
classes << book
OR
classes.add(book)