这可能是有史以来最愚蠢的问题,但我想知道是否有办法在函数(最好是装饰器)周围编写一个包装器,这样你就可以捕获局部变量的内部状态。该功能提出了一个例外。它会在创建本地时捕获它们,将它们腌制,然后在没有引发异常的情况下处理它们,或者如果发现任何异常则将它们写入文件。
这太过于幻想了,还是有人因这样的事情而被骗了?
答案 0 :(得分:5)
您可以捕获f_locals
variable on a frame in the traceback:
import sys
import functools
def capturelocals(func):
@functools.wraps(func)
def wrapperfunc(*args, **kw):
try:
return func(*args, **kw)
except Exception:
_, _, tb = sys.exc_info()
try:
while tb.tb_next is not None:
tb = tb.tb_next # find innermost frame
locals = tb.tb_frame.f_locals
print locals
finally:
del tb # prevent leaking tracebacks
raise
return wrapperfunc
证明它有效:
>>> @capturelocals
... def foobar():
... foo = 'bar'
... spam = 'eggs'
... raise ValueError('Bam!')
...
>>> foobar()
{'foo': 'bar', 'spam': 'eggs'}
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 5, in wrapperfunc
File "<stdin>", line 5, in foobar
ValueError: Bam!
答案 1 :(得分:1)
另一种选择是将函数作为参数传递给你有兴趣保存的变量,以防万一发生灾难性事件。
可能帮助您完成此操作的装饰器:
import os
try:
import cPickle as pickle
except ImportError:
import pickle
def save_args_if_exception(pickle_folder):
def real_decorator(function):
def wrapper(*args, **kwargs):
try:
function(*args, **kwargs)
except:
print 'FAILING SAFE: Saving arguments to folder:'
print pickle_folder
for arg_position, arg in enumerate(args, start=1):
arg_fname = os.path.join(pickle_folder, str(arg_position) +
'.pickle')
print 'Saving positional argument-{}'.format(arg_position)
with open(arg_fname, mode='wb') as f:
pickle.dump(arg, f)
print 'Saving keyword arguments (kwargs)'
with open(os.path.join(pickle_folder, 'kwargs.pickle'),
mode='wb') as f:
pickle.dump(kwargs, f)
raise # re-raise original exception
return wrapper
return real_decorator
@save_args_if_exception(os.getcwd())
def important_function(first_arg, second_arg=2, **kwargs):
print 'About to raise an exception!'
raise Exception
important_function(3)
请注意,在此示例中,second_arg
未保存到文件中,可能是因为Python处理默认参数的方式。根据您的情况,这可能是也可能不是有用的行为。
参考文献: