我有以下代码试图调整reportlab Platypus flowable文本的字体大小,直到它符合我给出的可用高度。但我发现Paragraph flowable并没有在递归的每个循环中保存它的style.fontSize属性,而且python包含无限递归。
def fits_space(w,h,aW,aH,p):
"""
Determines if inputted text fits in the space given for a paragraph
and if it doesn't, reduces the font-size until it does.
"""
if w<=aW and h<=aH:
# return font size to apply it to the para again
print "final font_size: %d" % p.style.fontSize
return p # now render the paragraph in the doctemplate
else:
p.style.fontSize -= 1
w,h = p.wrap(aW, aH)
fits_space(w,h,aW,aH,p)
def renderPage(name, text):
doc = SimpleDocTemplate("%s.pdf" % name)
parts = []
style = ParagraphStyle(name='fancy')
style.fontSize = 150
p = Paragraph(text, style)
aW = PAGE_WIDTH-4*inch # available width and height
aH = PAGE_HEIGHT-4*inch
w,h = p.wrap(aW, aH) # find required space
p = fits_space(w,h,aW,aH,p) # recursively fit the font size to the text
parts.append(p)
doc.build(parts)
任何人都可以让我知道为什么 - 在fits_space()函数中,在else子句中,当我调用p.wrap(aW,aH)时,输出的值与我将段落的fontSize递减1之前的值相同?当我减小字体大小时,包裹的高度肯定会更少?
我出错的任何想法?
更新 Nitzie的代码几乎可以只需要在我的情况下为style.leading添加一个缩放器:
def shrink_font_size(aW, aH, text, style):
"""Shrinks font size by using pdfmetrics to calculate the height
of a paragraph, given the font name, size, and available width."""
def break_lines(text, aW):
# simpleSplit calculates how reportlab will break up the lines for
# display in a paragraph, by using width/fontsize.
return simpleSplit(text, style.fontName, style.fontSize, aW)
def line_wrap(lines, style):
# Get overall width of text by getting stringWidth of longest line
width = stringWidth(max(lines), style.fontName, style.fontSize)
# Paragraph height can be calculated via line spacing and number of lines.
height = style.leading * len(lines)
return width, height
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)
while height > aH or width > aW:
style.fontSize -= 1
style.leading -= 1 # do this if you're leading is based on the fontSize
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)
TIA
答案 0 :(得分:4)
出于某种原因,p.wrap
在调用一次之后更改了字体大小后,似乎并没有真正重新计算高度/宽度。
我能够通过基于ReportLab的stringWidth
和splitLines
方法计算字体大小来获得工作版本。虽然这意味着它不再是递归的:
from reportlab.platypus import SimpleDocTemplate
from reportlab.lib.styles import ParagraphStyle
from reportlab.lib.units import inch
from reportlab.lib.pagesizes import A4
from reportlab.platypus import Paragraph
from reportlab.lib.utils import simpleSplit
from reportlab.pdfbase.pdfmetrics import stringWidth
def shrink_font_size(aW, aH, text, style):
"""Shrinks font size by using pdfmetrics to calculate the height
of a paragraph, given the font name, size, and available width."""
def break_lines(text, aW):
# simpleSplit calculates how reportlab will break up the lines for
# display in a paragraph, by using width/fontsize.
return simpleSplit(text, style.fontName, style.fontSize, aW)
def line_wrap(lines, style):
# Get overall width of text by getting stringWidth of longest line
width = stringWidth(max(lines), style.fontName, style.fontSize)
# Paragraph height can be calculated via line spacing and number of lines.
height = style.leading * len(lines)
return width, height
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)
while height > aH or width > aW:
style.fontSize -= 1
lines = break_lines(text, aW)
width, height = line_wrap(lines, style)
def renderPage(name, text):
doc = SimpleDocTemplate("%s.pdf" % name)
parts = []
# Wasn't sure where PAGE_WIDTH and PAGE_HEIGHT came from for OP,
# so I just used a standard A4 page measurement.
PAGE_WIDTH, PAGE_HEIGHT = A4
aW = PAGE_WIDTH - 4*inch # available width and height
aH = PAGE_HEIGHT - 4*inch
style = ParagraphStyle(name='fancy')
style.fontSize = 200
style.leading = 20
shrink_font_size(aW, aH, text, style)
p = Paragraph(text, style)
parts.append(p)
doc.build(parts)
if __name__ == "__main__":
renderPage('test', '12345689019283382848248284 842828428529392381472754 842828428529392381472754 842828428529392381472754\n' * 10)