我正在使用VS2012 / C#/ MVC 4。
我正在尝试发布“联系我们”表单而不刷新整个页面。一切都很好,如果我错过任何必填字段并且OnSuccess未被触发,则验证会在第一时间启动。在我成功发布表单(不缺少任何必填字段)后,即使验证失败(缺少必填字段),每次额外发布也会导致OnSuccess触发。红色感叹号显示正确,控制器“知道”它失败但ajax OnSuccess似乎不知道新的故障。
ContactUsForm.cshtml(partialView):
@model contactdemo.Models.ContactUsDetails
<div id="formContainer">
@using (Ajax.BeginForm("ContactUsForm", new AjaxOptions { UpdateTargetId = "formContainer", OnSuccess = "displaySuccess" }))
{
<strong>Send To: </strong>
<div>
@Html.DevExpress().ComboBoxFor(model => model.ContactID,
settings =>
{
settings.ShowModelErrors = true;
settings.Width = System.Web.UI.WebControls.Unit.Percentage(100);
settings.Name = "ContactID";
settings.Properties.ValueField = "ContactID";
settings.Properties.ValueType = typeof(int);
settings.Properties.TextField = "ContactName";
settings.ControlStyle.CssClass = "contactUsCombo";
}).BindList(Session["Names"]).GetHtml()
</div>
<div>
@Html.DevExpress().LabelFor(m => m.Subject).GetHtml()
@Html.DevExpress().TextBoxFor(m => m.Subject,
settings =>
{
settings.ShowModelErrors = true;
settings.Width = System.Web.UI.WebControls.Unit.Percentage(100);
settings.ControlStyle.CssClass = "subjectText";
}).GetHtml()
</div>
<div>
@Html.DevExpress().LabelFor(m => m.Message).GetHtml()
@Html.DevExpress().MemoFor(m => m.Message,
settings =>
{
settings.ShowModelErrors = true;
settings.Height = 50;
settings.Width = System.Web.UI.WebControls.Unit.Percentage(100);
settings.ControlStyle.CssClass = "memoText";
}).GetHtml()
</div>
<div>
@Html.DevExpress().Button(
settings =>
{
settings.Name = "btnSubmit";
settings.Text = "Send Message";
settings.UseSubmitBehavior = true;
settings.ControlStyle.CssClass = "contactUsCombo";
}).GetHtml()
</div>
}
HomeController.cs:
namespace contactdemo.Controllers
{
[OutputCacheAttribute(VaryByParam = "*", Duration = 1, NoStore = true)]
public class HomeController : Controller
{
<snip...>
[HttpGet]
[OutputCache(Duration = 60, VaryByParam = "*")]
public ActionResult ContactUsForm()
{
return PartialView(new ContactUsDetails());
}
[HttpPost]
public ActionResult ContactUsForm(ContactUsDetails data)
{
if (ModelState.IsValid)
{
return PartialView(new ContactUsDetails());
}
else
{
return PartialView(data);
}
}
}
Index.cshtml:
<script src="@Url.Content("~/Scripts/jquery.unobtrusive-ajax.min.js")" type="text/javascript"></script>
<script type="text/javascript">
function displaySuccess(result) {
alert("Sent Successfully");
}
</script>
答案 0 :(得分:2)
确保在displaySuccess
回调中将不显眼的验证处理程序重新附加到DOM的新添加内容中:
function displaySuccess(result) {
$('#formContainer form').removeData('validator');
$('#formContainer form').removeData('unobtrusiveValidation');
$.validator.unobtrusive.parse('#formContainer form');
alert('Sent Successfully');
}
您需要这样做的原因是因为您在AJAX回调之后使用新的部分刷新DOM的内容,并且不引人注意的验证框架除非您告诉它,否则无法知道这些新元素。您还可以查看similar answer
。