我想将以下xml解组为另一个父对象,如下所示。但它总是返回NULL。
传入XML:
<contentFiles>
<contentFile>
<contentFileName>cwb_reg_content_IB20C0F504A9A11E281E4C8BF76F4977C.pdf</contentFileName>
<title><![CDATA[SEC No-Action Guidance Expanding the Definition of “Ready Market” for Certain Foreign Equity Securities]]></title>
<sourcePublicationDate>20121219</sourcePublicationDate>
<alternateDocNumbers>
<alternateDocNumber>12345-b</alternateDocNumber>
</alternateDocNumbers>
<citesAffected>
<cite>SEA Rule 15c3-1</cite>
</citesAffected>
</contentFile>
</contentFiles>
与<contentFiles>
@XmlRootElement(name = "contentFiles")
public class RtSuperQuickMetadata
{
private List<RtSuperQuickMetadataItem> rtSuperQuickMetadataItems;
public RtSuperQuickMetadata()
{
rtSuperQuickMetadataItems = new ArrayList<RtSuperQuickMetadataItem>();
}
public List<RtSuperQuickMetadataItem> getRtSuperQuickMetadataItems()
{
return rtSuperQuickMetadataItems;
}
public void setRtSuperQuickMetadataItems(
List<RtSuperQuickMetadataItem> rtSuperQuickMetadataItems)
{
this.rtSuperQuickMetadataItems = rtSuperQuickMetadataItems;
}
}
与<contentFile>
@XmlRootElement(name = "contentFile")
public class RtSuperQuickMetadataItem
{
private String contentFileName;
private String title;
private String sourcePublicationDate;
private List<AlternateDocNumber> alternateDocNumbers;
private List<Cite> citesAffected;
public RtSuperQuickMetadataItem()
{
alternateDocNumbers = new ArrayList<AlternateDocNumber>();
citesAffected = new ArrayList<Cite>();
}
public List<AlternateDocNumber> getAlternateDocNumbers()
{
return alternateDocNumbers;
}
public List<Cite> getCitesAffected()
{
return citesAffected;
}
public String getContentFileName()
{
return contentFileName;
}
public String getSourcePublicationDate()
{
return sourcePublicationDate;
}
public String getTitle()
{
return title;
}
public void setAlternateDocNumbers(List<AlternateDocNumber> alternateDocNumbers)
{
this.alternateDocNumbers = alternateDocNumbers;
}
public void setCitesAffected(List<Cite> citesAffected)
{
this.citesAffected = citesAffected;
}
public void setContentFileName(String contentFileName)
{
this.contentFileName = contentFileName;
}
public void setSourcePublicationDate(String sourcePublicationDate)
{
this.sourcePublicationDate = sourcePublicationDate;
}
public void setTitle(String title)
{
this.title = title;
}
}
@XmlRootElement(name = "alternateDocNumber")
class AlternateDocNumber
{
private String alternateDocNumber;
public String getAlternateDocNumber()
{
return alternateDocNumber;
}
public void setAlternateDocNumber(String alternateDocNumber)
{
this.alternateDocNumber = alternateDocNumber;
}
@Override
public String toString()
{
return "AlternateDocNumber [alternateDocNumber=" + alternateDocNumber + "]";
}
}
@XmlRootElement(name = "cite")
class Cite
{
private String cite;
public String getCite()
{
return cite;
}
public void setCite(String cite)
{
this.cite = cite;
}
@Override
public String toString()
{
return "Cite [cite=" + cite + "]";
}
}
使用JAXB的Unmarshaller代码:
public RtSuperQuickMetadata unmarshallXml(final File metadataFile)
throws JAXBException, FileNotFoundException
{
RtSuperQuickMetadata rtSuperQuickMetadata = null;
try
{
JAXBContext jc = JAXBContext.newInstance(RtSuperQuickMetadata.class);
Unmarshaller um = jc.createUnmarshaller();
rtSuperQuickMetadata =
(RtSuperQuickMetadata) um.unmarshal(metadataFile);
}
catch (JAXBException e)
{
String msg = "Malformed XML supplied as Metadata" + " Msg " + e.getMessage();
LOG.error(msg, e);
throw new RuntimeException(msg, e);
}
return rtSuperQuickMetadata;
}
答案 0 :(得分:3)
你有太多XmlRootElements
,你通常只希望将它与top元素一起使用。您要做的是将孩子标记为XmlElement
。
从除根元素之外的所有元素(即XmlRootElement
)中删除RtSuperQuickMetadata
注释,并在其将加载它们的类中使用XmlElement
标记它们
因此,作为一个例子,以下是RtSuperQuickMetadata
类的外观:
@XmlRootElement(name = "contentFiles")
class RtSuperQuickMetadata
{
private List<RtSuperQuickMetadataItem> rtSuperQuickMetadataItems;
public RtSuperQuickMetadata()
{
rtSuperQuickMetadataItems = new ArrayList<RtSuperQuickMetadataItem>();
}
@XmlElement(name = "contentFile")
public List<RtSuperQuickMetadataItem> getRtSuperQuickMetadataItems()
{
return rtSuperQuickMetadataItems;
}
public void setRtSuperQuickMetadataItems(
List<RtSuperQuickMetadataItem> rtSuperQuickMetadataItems)
{
this.rtSuperQuickMetadataItems = rtSuperQuickMetadataItems;
}
}
将此原则转移到alternateDocNumbers
和citesAffected
。
如果您想查看Unmarshaller
如何根据您的注释对XML进行格式化的示例,您可以在代码中创建结构并使用Marshaller
。这是一个快速而丑陋的例子:
RtSuperQuickMetadata rtSuperQuickMetadata = new RtSuperQuickMetadata();
List<RtSuperQuickMetadataItem> rtSuperQuickMetadataItems = new ArrayList<RtSuperQuickMetadataItem>();
rtSuperQuickMetadata.setRtSuperQuickMetadataItems(rtSuperQuickMetadataItems);
RtSuperQuickMetadataItem item = new RtSuperQuickMetadataItem();
rtSuperQuickMetadataItems.add(item);
ArrayList<Cite> cites = new ArrayList<Cite>();
Cite cite = new Cite();
cite.setCiteStr("MyCite");
cites.add(cite);
item.setCitesAffected(cites);
Marshaller m = jaxbContext.createMarshaller();
m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
m.marshal(rtSuperQuickMetadata, System.out);
这会将结果输出到System.out
。你可以把它放在一个文件中,不管你需要什么。
答案 1 :(得分:1)
我已添加此答案,以解决您在answer given by cklab上发表的评论后续问题。
我有另一个问题。为什么jaxb不会自动分配内存 对于包含在对象中的列表。为什么我们需要分配内存 在它的构造函数中?
你不需要,见下文。
在解组这些项目时,以下内容未保存到 元数据对象。 12我 需要添加另一个元素才能生成?
请参阅下面的地图。
<强> RtSuperQuickMetadata 强>
import java.util.*;
import javax.xml.bind.annotation.*;
@XmlRootElement(name = "contentFiles")
public class RtSuperQuickMetadata {
private List<RtSuperQuickMetadataItem> rtSuperQuickMetadataItems;
@XmlElement(name="contentFile")
public List<RtSuperQuickMetadataItem> getRtSuperQuickMetadataItems() {
return rtSuperQuickMetadataItems;
}
public void setRtSuperQuickMetadataItems(
List<RtSuperQuickMetadataItem> rtSuperQuickMetadataItems) {
this.rtSuperQuickMetadataItems = rtSuperQuickMetadataItems;
}
}
<强> RtSuperQuickMetadataItem 强>
import java.util.List;
import javax.xml.bind.annotation.XmlType;
@XmlType(propOrder={"contentFileName", "title", "sourcePublicationDate", "alternateDocNumbers", "citesAffected"})
public class RtSuperQuickMetadataItem {
private String contentFileName;
private String title;
private String sourcePublicationDate;
private List<AlternateDocNumber> alternateDocNumbers;
private List<Cite> citesAffected;
public List<AlternateDocNumber> getAlternateDocNumbers() {
return alternateDocNumbers;
}
public List<Cite> getCitesAffected() {
return citesAffected;
}
public String getContentFileName() {
return contentFileName;
}
public String getSourcePublicationDate() {
return sourcePublicationDate;
}
public String getTitle() {
return title;
}
public void setAlternateDocNumbers(
List<AlternateDocNumber> alternateDocNumbers) {
this.alternateDocNumbers = alternateDocNumbers;
}
public void setCitesAffected(List<Cite> citesAffected) {
this.citesAffected = citesAffected;
}
public void setContentFileName(String contentFileName) {
this.contentFileName = contentFileName;
}
public void setSourcePublicationDate(String sourcePublicationDate) {
this.sourcePublicationDate = sourcePublicationDate;
}
public void setTitle(String title) {
this.title = title;
}
}
<强> AlternateDocNumber 强>
class AlternateDocNumber {
private String alternateDocNumber;
public String getAlternateDocNumber() {
return alternateDocNumber;
}
public void setAlternateDocNumber(String alternateDocNumber) {
this.alternateDocNumber = alternateDocNumber;
}
}
<强>引用强>
class Cite {
private String cite;
public String getCite() {
return cite;
}
public void setCite(String cite) {
this.cite = cite;
}
}