Question

我需要使用attoparsec解析固定长度的字段，但我现在正在努力编译器。我仍然是新手，下面的代码是我最接近的解决方案：

> {-# LANGUAGE OverloadedStrings #-}
> import Control.Applicative
> import Data.Text as T
> import Data.Attoparsec.Combinator
> import Data.Attoparsec.Text hiding (take)
> import Data.Char
> import Prelude hiding (take)
>
> type City = Text
> type Ready = Bool
> data CityReady = CR City Ready deriving Show
>
> input = T.unlines ["#London              1",
>                    "#Seoul               0",
>                    "#Tokyo               0",
>                    "#New York            1"]
>
> parseCityReady = many $ CR <$> cityParser <*> readyParser <* endOfLine
>
> cityParser = char '#' *>
>              takeTill isSpace <*
>              skipWhile isHorizontalSpace
>
>
> readyParser = char '1' *> pure True  <|> char '0' *> pure False
>
> main =
>   case parseOnly parseCityReady input of
>      Left err  -> print err
>      Right xs  -> mapM_ print xs
>

这一切都很棒，但它只返回没有空格的城市。

CR "London" True
CR "Seoul" False
CR "Tokyo" False

我尝试使用applicative为City文本字符串取20个字符

> cityParser = char '#' *>
>              take 20

甚至是do syntax

> cityParser = do char '#'
>                 city <- take 20
>                 return city

但这两种方法都无法使用此错误进行编译：

Couldn't match expected type `attoparsec-0.10.4.0:Data.Attoparsec.Internal.Types.Parser
                                Text b0'
            with actual type `Text -> Text'
In the return type of a call of `take'
Probable cause: `take' is applied to too few arguments
In the second argument of `(*>)', namely `take 20'
In the expression: char '#' *> take 20

当Text -> Text的{{1}}类型为take时，是什么导致ghc要求Int -> Text -> Text？

如何在applicative和do-syntax中解决它？

Answer 1

所以，你的问题是你隐藏了take的几个版本功能。特别是，您隐藏take来自attoparsec 而不是take模块中的Text函数。你需要做的就是像这样改变你的进口

> import Control.Applicative
> import Data.Attoparsec.Combinator
> import Data.Attoparsec.Text
> import Data.Char
> import Data.Text as T hiding (take)
> import Prelude hiding (take)

使用attoparsec解析固定长度的文本

1 个答案: