Swift中的URL验证

Question

在我正在开发的iPhone应用程序中，有一个设置可以输入URL，因为形式和＆amp;功能此URL需要在线和离线验证。

到目前为止，我还没有找到任何验证网址的方法，所以问题是;

如何在线和离线验证iPhone（Objective-C）上的URL输入？

Answer 1

为什么不依靠Foundation.framework？

完成工作并且不需要RegexKit：

NSURL *candidateURL = [NSURL URLWithString:candidate];
// WARNING > "test" is an URL according to RFCs, being just a path
// so you still should check scheme and all other NSURL attributes you need
if (candidateURL && candidateURL.scheme && candidateURL.host) {
  // candidate is a well-formed url with:
  //  - a scheme (like http://)
  //  - a host (like stackoverflow.com)
}

根据Apple文档：

URLWithString：创建并返回用a初始化的NSURL对象   提供字符串。

+ (id)URLWithString:(NSString *)URLString

<强>参数

URLString：用于初始化NSURL对象的字符串。必须符合RFC 2396.此方法根据RFC 1738和1808解析URLString。

返回值

使用URLString初始化的NSURL对象。 如果字符串格式错误，则返回nil。

Answer 2

感谢this post，您可以避免使用RegexKit。这是我的解决方案（适用于iOS＆gt; 3.0的iphone开发）：

- (BOOL) validateUrl: (NSString *) candidate {
    NSString *urlRegEx =
    @"(http|https)://((\\w)*|([0-9]*)|([-|_])*)+([\\.|/]((\\w)*|([0-9]*)|([-|_])*))+";
    NSPredicate *urlTest = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", urlRegEx]; 
    return [urlTest evaluateWithObject:candidate];
}

如果您想在下面给出Swift我的解决方案：

 func isValidUrl(url: String) -> Bool {
        let urlRegEx = "^(https?://)?(www\\.)?([-a-z0-9]{1,63}\\.)*?[a-z0-9][-a-z0-9]{0,61}[a-z0-9]\\.[a-z]{2,6}(/[-\\w@\\+\\.~#\\?&/=%]*)?$"
        let urlTest = NSPredicate(format:"SELF MATCHES %@", urlRegEx)
        let result = urlTest.evaluate(with: url)
        return result
    }

Answer 3

不是编写自己的正则表达式，而是依赖Apple。我一直在使用NSString上的类别，使用NSDataDetector来测试字符串中是否存在链接。如果NSDataDetector找到的链接范围等于整个字符串的长度，那么它就是一个有效的URL。

- (BOOL)isValidURL {
    NSUInteger length = [self length];
    // Empty strings should return NO
    if (length > 0) {
        NSError *error = nil;
        NSDataDetector *dataDetector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeLink error:&error];
        if (dataDetector && !error) {
            NSRange range = NSMakeRange(0, length);
            NSRange notFoundRange = (NSRange){NSNotFound, 0};
            NSRange linkRange = [dataDetector rangeOfFirstMatchInString:self options:0 range:range];
            if (!NSEqualRanges(notFoundRange, linkRange) && NSEqualRanges(range, linkRange)) {
                return YES;
            }
        }
        else {
            NSLog(@"Could not create link data detector: %@ %@", [error localizedDescription], [error userInfo]);
        }
    }
    return NO;
}

Answer 4

我的解决方案 Swift ：

func validateUrl (stringURL : NSString) -> Bool {

    var urlRegEx = "((https|http)://)((\\w|-)+)(([.]|[/])((\\w|-)+))+"
    let predicate = NSPredicate(format:"SELF MATCHES %@", argumentArray:[urlRegEx])
    var urlTest = NSPredicate.predicateWithSubstitutionVariables(predicate)

    return predicate.evaluateWithObject(stringURL)
}

对于测试：

var boolean1 = validateUrl("http.s://www.gmail.com")
var boolean2 = validateUrl("https:.//gmailcom")
var boolean3 = validateUrl("https://gmail.me.")
var boolean4 = validateUrl("https://www.gmail.me.com.com.com.com")
var boolean6 = validateUrl("http:/./ww-w.wowone.com")
var boolean7 = validateUrl("http://.www.wowone")
var boolean8 = validateUrl("http://www.wow-one.com")
var boolean9 = validateUrl("http://www.wow_one.com")
var boolean10 = validateUrl("http://.")
var boolean11 = validateUrl("http://")
var boolean12 = validateUrl("http://k")

结果：

false
false
false
true
false
false
true
true
false
false
false

Answer 5

使用此 -

NSString *urlRegEx = @"http(s)?://([\\w-]+\\.)+[\\w-]+(/[\\w- ./?%&amp;=]*)?";

Answer 6

我使用RegexKit解决了问题，并构建了一个快速正则表达式来验证网址;

NSString *regexString = @"(http|https)://((\\w)*|([0-9]*)|([-|_])*)+([\\.|/]((\\w)*|([0-9]*)|([-|_])*))+";
NSString *subjectString = brandLink.text;
NSString *matchedString = [subjectString stringByMatching:regexString];

然后我检查matchesString是否等于subjectString，如果是这样，url是有效的：）

如果我的正则表达式错误，请纠正我;）

Answer 7

奇怪的是，我在这里找不到一个非常简单的解决方案，但仍然可以处理http / https个链接。

请记住，这不是一个完美的解决方案，但它适用于以下情况。总之，正则表达式测试URL是以http://还是https://开头，然后检查至少1个字符，然后检查一个点，然后再检查至少1个字符。没有空格。

+ (BOOL)validateLink:(NSString *)link
{
    NSString *regex = @"(?i)(http|https)(:\\/\\/)([^ .]+)(\\.)([^ \n]+)";
    NSPredicate *predicate = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", regex];
    return [predicate evaluateWithObject:link];
}

针对这些网址测试了VALID：

@"HTTP://FOO.COM",
@"HTTPS://FOO.COM",
@"http://foo.com/blah_blah",
@"http://foo.com/blah_blah/",
@"http://foo.com/blah_blah_(wikipedia)",
@"http://foo.com/blah_blah_(wikipedia)_(again)",
@"http://www.example.com/wpstyle/?p=364",
@"https://www.example.com/foo/?bar=baz&inga=42&quux",
@"http://✪df.ws/123",
@"http://userid:password@example.com:8080",
@"http://userid:password@example.com:8080/",
@"http://userid@example.com",
@"http://userid@example.com/",
@"http://userid@example.com:8080",
@"http://userid@example.com:8080/",
@"http://userid:password@example.com",
@"http://userid:password@example.com/",
@"http://142.42.1.1/",
@"http://142.42.1.1:8080/",
@"http://➡.ws/䨹",
@"http://⌘.ws",
@"http://⌘.ws/",
@"http://foo.com/blah_(wikipedia)#cite-",
@"http://foo.com/blah_(wikipedia)_blah#cite-",
@"http://foo.com/unicode_(✪)_in_parens",
@"http://foo.com/(something)?after=parens",
@"http://☺.damowmow.com/",
@"http://code.google.com/events/#&product=browser",
@"http://j.mp",
@"http://foo.bar/?q=Test%20URL-encoded%20stuff",
@"http://مثال.إختبار",
@"http://例子.测试",
@"http://उदाहरण.परीक्षा",
@"http://-.~_!$&'()*+,;=:%40:80%2f::::::@example.com",
@"http://1337.net",
@"http://a.b-c.de",
@"http://223.255.255.254"

针对这些网址测试了INVALID：

@"",
@"foo",
@"ftp://foo.com",
@"ftp://foo.com",
@"http://..",
@"http://..",
@"http://../",
@"//",
@"///",
@"http://##/",
@"http://.www.foo.bar./",
@"rdar://1234",
@"http://foo.bar?q=Spaces should be encoded",
@"http:// shouldfail.com",
@":// should fail"

网址来源： https://mathiasbynens.be/demo/url-regex

Answer 8

如果您不想http或https或www

，可以使用此功能

NSString *urlRegEx = @"^(http(s)?://)?((www)?\.)?[\w]+\.[\w]+";

例如

- (void) testUrl:(NSString *)urlString{
    NSLog(@"%@: %@", ([self isValidUrl:urlString] ? @"VALID" : @"INVALID"), urlString);
}

- (void)doTestUrls{
    [self testUrl:@"google"];
    [self testUrl:@"google.de"];
    [self testUrl:@"www.google.de"];
    [self testUrl:@"http://www.google.de"];
    [self testUrl:@"http://google.de"];
}

输出：

INVALID: google
VALID: google.de
VALID: www.google.de
VALID: http://www.google.de
VALID: http://google.de

Answer 9

Lefakir的解决方案有一个问题。他的正则表达式与“http://instagram.com/p/4Mz3dTJ-ra/”不匹配。 Url组件结合了数字和文字字符。他的正则表达式失败了。

这是我的改进。

"(http|https)://((\\w)*|([0-9]*)|([-|_])*)+([\\.|/]((\\w)*|([0-9]*)|([-|_])*)+)+(/)?(\\?.*)?"

Answer 10

我发现最简单的方法就是这样：

CDbl

Answer 11

下面的代码可以让您找到有效的网址

      NSPredicate *websitePredicate = [NSPredicate predicateWithFormat:@"SELF MATCHES %@",@"^(((((h|H)(t|T){2}(p|P)s?)|((f|F)(t|T)(p|P)))://(w{3}.)?)|(w{3}.))[A-Za-z0-9]+(.[A-Za-z0-9-:;\?#_]+)+"];
     if ([websitePredicate evaluateWithObject:##MY_STRING##])
     {
       printf"Valid"
     }

用于此类网址

Answer 12

Tweibed Vaibhav支持G +链接的答案：

NSString *urlRegEx = @"http(s)?://([\\w-]+\\.)+[\\w-]+(/[\\w-\\+ ./?%&=]*)?";

Answer 13

目标C

- (BOOL)validateUrlString:(NSString*)urlString
{
    if (!urlString)
    {
        return NO;
    }

    NSDataDetector *linkDetector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeLink error:nil];

    NSRange urlStringRange = NSMakeRange(0, [urlString length]);
    NSMatchingOptions matchingOptions = 0;

    if (1 != [linkDetector numberOfMatchesInString:urlString options:matchingOptions range:urlStringRange])
    {
        return NO;
    }

    NSTextCheckingResult *checkingResult = [linkDetector firstMatchInString:urlString options:matchingOptions range:urlStringRange];

    return checkingResult.resultType == NSTextCheckingTypeLink && NSEqualRanges(checkingResult.range, urlStringRange);
}

希望这有帮助！

Answer 14

批准的答案不正确。我有一个带有“ - ”的URL，验证失败。

Answer 15

在上面的解决方案中，没有/最后的某些URL未被检测为正确的URL。所以这可能会有所帮助。

  extension String {
    func isValidURL() -> Bool{
        let length:Int = self.characters.count
        var err:NSError?
        var dataDetector:NSDataDetector? = NSDataDetector()
        do{
            dataDetector = try NSDataDetector(types: NSTextCheckingType.Link.rawValue)
        }catch{
            err = error as NSError
        }
        if dataDetector != nil{
            let range = NSMakeRange(0, length)
            let notFoundRange = NSRange(location: NSNotFound, length: 0)
            let linkRange = dataDetector?.rangeOfFirstMatchInString(self, options: NSMatchingOptions.init(rawValue: 0), range: range)
            if !NSEqualRanges(notFoundRange, linkRange!) && NSEqualRanges(range, linkRange!){
                return true
            }
        }else{
            print("Could not create link data detector: \(err?.localizedDescription): \(err?.userInfo)")
        }

        return false
    }
}

Answer 16

Swift中的URL验证

详细

Xcode 8.2.1，Swift 3

代码

枚举URLSchemes：String

import Foundation

enum URLSchemes: String {
    case http = "http://", https = "https://", ftp = "ftp://", unknown = "unknown://"

    static func detectScheme(urlString: String) -> URLSchemes {

        if URLSchemes.isSchemeCorrect(urlString: urlString, scheme: .http) {
            return .http
        }
        if URLSchemes.isSchemeCorrect(urlString: urlString, scheme: .https) {
            return .https
        }
        if URLSchemes.isSchemeCorrect(urlString: urlString, scheme: .ftp) {
            return .ftp
        }
        return .unknown
    }

    static func getAllSchemes(separetedBy separator: String) -> String {
        return "\(URLSchemes.http.rawValue)\(separator)\(URLSchemes.https.rawValue)\(separator)\(URLSchemes.ftp.rawValue)"
    }

    private static func isSchemeCorrect(urlString: String, scheme: URLSchemes) -> Bool {
        if urlString.replacingOccurrences(of: scheme.rawValue, with: "") == urlString {
            return false
        }
        return true
    }
}

扩展名字符串

import Foundation

extension String {

    var isUrl: Bool {

        // for http://regexr.com checking
        // (?:(?:https?|ftp):\/\/)(?:xn--)?(?:\S+(?::\S*)?@)?(?:(?!10(?:\.\d{1,3}){3})(?!127(?:\.\d{1,3}){3})(?!169\.254(?:\.\d{1,3}){2})(?!192\.168(?:\.\d{1,3}){2})(?!172\.(?:1[6-9]|2\d|3[0-1])(?:\.\d{1,3}){2})(?:[1-9]\d?|1\d\d|2[01]\d|22[0-3])(?:\.(?:1?\d{1,2}|2[0-4]\d|25[0-5])){2}(?:\.(?:[1-9]\d?|1\d\d|2[0-4]\d|25[0-4]))|(?:(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)(?:\.(?:[a-z\u00a1-\uffff0-9]+-?)*[a-z\u00a1-\uffff0-9]+)*(?:\.(?:[#-z\u00a1-\uffff]{2,})))(?::\d{2,5})?(?:\/[^\s]*)?

        let schemes = URLSchemes.getAllSchemes(separetedBy: "|").replacingOccurrences(of: "://", with: "")
        let regex = "(?:(?:\(schemes)):\\/\\/)(?:xn--)?(?:\\S+(?::\\S*)?@)?(?:(?!10(?:\\.\\d{1,3}){3})(?!127(?:\\.\\d{1,3}){3})(?!169\\.254(?:\\.\\d{1,3}){2})(?!192\\.168(?:\\.\\d{1,3}){2})(?!172\\.(?:1[6-9]|2\\d|3[0-1])(?:\\.\\d{1,3}){2})(?:[1-9]\\d?|1\\d\\d|2[01]\\d|22[0-3])(?:\\.(?:1?\\d{1,2}|2[0-4]\\d|25[0-5])){2}(?:\\.(?:[1-9]\\d?|1\\d\\d|2[0-4]\\d|25[0-4]))|(?:(?:[a-z\\u00a1-\\uffff0-9]+-?)*[a-z\\u00a1-\\uffff0-9]+)(?:\\.(?:[a-z\\u00a1-\\uffff0-9]+-?)*[a-z\\u00a1-\\uffff0-9]+)*(?:\\.(?:[#-z\\u00a1-\\uffff]{2,})))(?::\\d{2,5})?(?:\\/[^\\s]*)?"


        let regularExpression = try! NSRegularExpression(pattern: regex, options: [])
        let range = NSRange(location: 0, length: self.characters.count)
        let matches = regularExpression.matches(in: self, options: [], range: range)
        for match in matches {
            if range.location == match.range.location && range.length == match.range.length {
                return true
            }
        }
        return false
    }

    var toURL: URL? {

        let urlChecker: (String)->(URL?) = { url_string in
            if url_string.isUrl, let url = URL(string: url_string) {
                return url
            }
            return nil
        }

        if !contains(".") {
            return nil
        }

        if let url = urlChecker(self) {
            return url
        }

        let scheme = URLSchemes.detectScheme(urlString: self)
        if scheme == .unknown {
            let newEncodedString = URLSchemes.http.rawValue + self
            if let url = urlChecker(newEncodedString) {
                return url
            }
        }

        return nil
    }
}

用法

 func tests() {

    chekUrl(urlString:"http://example.com")
    chekUrl(urlString:"https://example.com")
    chekUrl(urlString:"http://example.com/dir/file.php?var=moo")
    chekUrl(urlString:"http://xn--h1aehhjhg.xn--d1acj3b")
    chekUrl(urlString:"http://www.example.com/wpstyle/?p=364")
    chekUrl(urlString:"http://-.~_!$&'()*+,;=:%40:80%2f::::::@example.com")
    chekUrl(urlString:"http://example.com")
    chekUrl(urlString:"http://xn--d1acpjx3f.xn--p1ai")
    chekUrl(urlString:"http://xn--74h.damowmow.com/")
    chekUrl(urlString:"ftp://example.com:129/myfiles")
    chekUrl(urlString:"ftp://user:pass@site.com:21/file/dir")
    chekUrl(urlString:"ftp://ftp.example.com:2828/asdah%20asdah.gif")
    chekUrl(urlString:"http://142.42.1.1:8080/")
    chekUrl(urlString:"http://142.42.1.1/")
    chekUrl(urlString:"http://userid:password@example.com:8080")
    chekUrl(urlString:"http://userid@example.com")
    chekUrl(urlString:"http://userid@example.com:8080")
    chekUrl(urlString:"http://foo.com/blah_(wikipedia)#cite-1")
    chekUrl(urlString:"http://foo.com/(something)?after=parens")

    print("\n----------------------------------------------\n")

    chekUrl(urlString:".")
    chekUrl(urlString:" ")
    chekUrl(urlString:"")
    chekUrl(urlString:"-/:;()₽&@.,?!'{}[];'<>+_)(*#^%$")
    chekUrl(urlString:"localhost")
    chekUrl(urlString:"yandex.")
    chekUrl(urlString:"коряга")
    chekUrl(urlString:"http:///a")
    chekUrl(urlString:"ftps://foo.bar/")
    chekUrl(urlString:"rdar://1234")
    chekUrl(urlString:"h://test")
    chekUrl(urlString:":// should fail")
    chekUrl(urlString:"http://-error-.invalid/")
    chekUrl(urlString:"http://.www.example.com/")
}

func chekUrl(urlString: String) {
    var result = ""
    if urlString.isUrl {
        result += "url: "
    } else {
        result += "not url: "
    }
    result += "\"\(urlString)\""
    print(result)
}

结果

Answer 17

我在Swift 5中的解决方案：

extension String {
    func isValidUrl() -> Bool {
        do {
            let detector = try NSDataDetector(types: NSTextCheckingResult.CheckingType.link.rawValue)
            // check if the string has link inside
            return detector.numberOfMatches(in: self, options: [], range: .init( location: 0, length: utf16.count)) > 0
        } catch {
            print("Error during NSDatadetector initialization \(error)" )
        }
        return false
    }
}

Answer 18

func checkValidUrl(_ strUrl: String) -> Bool {
    let urlRegEx: String = "(http|https)://((\\w)*|([0-9]*)|([-|_])*)+([\\.|/]((\\w)*|([0-9]*)|([-|_])*))+"
    let urlTest = NSPredicate(format: "SELF MATCHES %@", urlRegEx)
    return urlTest.evaluate(with: strUrl)
}

Answer 19

您是否要检查用户输入的内容是否为网址？它可以像正则表达式一样简单，例如检查字符串是否包含www.（这是yahoo messenger检查用户状态是否为链接的方式）
希望有所帮助

Answer 20

将@ Anthony的答案扩展到swift，我在String上写了一个类别，返回一个可选的NSURL。如果nil无法验证为网址，则返回值为String。

import Foundation

// A private global detector variable which can be reused.
private let detector = try! NSDataDetector(types: NSTextCheckingType.Link.rawValue)

extension String {
  func URL() -> NSURL? {
    let textRange = NSMakeRange(0, self.characters.count)
    guard let URLResult = detector.firstMatchInString(self, options: [], range: textRange) else {
      return nil
    }

    // This checks that the whole string is the detected URL. In case
    // you don't have such a requirement, you can remove this code
    // and return the URL from URLResult.
    guard NSEqualRanges(URLResult.range, textRange) else {
      return nil
    }

    return NSURL(string: self)
  }
}

Answer 21

我创建了UITextField的继承类，它可以使用正则表达式字符串处理所有类型的验证。在这里你只需要按顺序给它们所有正则表达式字符串以及它们在验证失败时要显示的消息。您可以查看我的博客以获取更多信息，它将真正帮助您

http://dhawaldawar.wordpress.com/2014/06/11/uitextfield-validation-ios/

Answer 22

自私地，我建议使用KSURLFormatter实例验证输入，并将其转换为NSURL可以处理的内容。

如何在iPhone上验证网址

22 个答案:

Swift中的URL验证

详细

代码

用法

结果