Question

我得到了一个带有contextMenu的简单ListBox：

<ListBox BorderThickness="1" BorderBrush="Gray" SelectionChanged="TableList_SelectionChanged"   Grid.Column="0" x:Name="TableList">

            <ListBox.ContextMenu>
                <ContextMenu>
                    <MenuItem Click="MenuItem_Click"  Header="Ajouter"/>
                    <MenuItem Click="MenuItem_Click_1" Header="Supprimer"/>
                </ContextMenu>
            </ListBox.ContextMenu>

            <ListBox.ItemTemplate>
                <DataTemplate>
                    <StackPanel Orientation="Horizontal">
                        <Image Name="Image" Height="12px" Width="12px" Source="Apply.gif">
                            <Image.Margin>
                                <Thickness Right="10"></Thickness>
                            </Image.Margin>
                        </Image>
                        <TextBlock Text="{Binding Path=Content}" />
                    </StackPanel>
                </DataTemplate>
             </ListBox.ItemTemplate>

        </ListBox>

我试图从上下文菜单操作的Handler（任何操作）中检索所选ListBoxItem中的“Image”控件。处理程序是：

 'Dim ListBox As ListBox = DirectCast(sender.Parent, System.Windows.Controls.ContextMenu).PlacementTarget
    Dim ListBox As ListBox = Me.TableList
    Dim myListBoxItem As ListBoxItem = CType(ListBox.ItemContainerGenerator.ContainerFromItem(ListBox.Items.CurrentItem), ListBoxItem)

    ' Getting the ContentPresenter of myListBoxItem
    Dim myContentPresenter As ContentPresenter = FindVisualChild(Of ContentPresenter)(ListBox)

    ' Finding textBlock from the DataTemplate that is set on that ContentPresenter
    Dim myDataTemplate As DataTemplate = myContentPresenter.ContentTemplate

根据这个link形式的MSDN，我可以从DataTemplate中调用“findName”方法。但变量“myDataTemplate”是Nothing ......

我做错了什么？感谢

Answer 1

您将在此行中获取ListBox的内容演示者而不是ListBoxItem：

Dim myContentPresenter As ContentPresenter = FindVisualChild（Of ContentPresenter）（ListBox）

WPF ListBox ContentPresenter.ContentTemplate什么都没有

1 个答案: