如何在c ++中使用/创建unique_lock?

时间:2013-02-05 13:59:08

标签: c++ c++11 locking

请问,有人可以解释如何在c ++中使用和创建unique_lock吗? 它应该用于互斥监视器的任何过程,并能够对条件变量执行wait()...我不是从文档中了解我应该如何创建它。是必要的互斥?这是一个伪代码:

/* compile with g++, flags -std=c++0x -lpthread */

#include <condition_variable>
#include <mutex>
#include <thread>
#include <iostream>
#include <string.h>
#include <unistd.h>

class monitorTh {

private:

    std::mutex m;
    std::condition_variable waitP;
    std::condition_variable waitC;
    char element[32];
    std::unique_lock::unique_lock l;

public:
    void produce(char* elemProd) {
        l.lock();
        if (/*already_present_element*/) {
            waitP.wait(l);
        }
        else {/*produce element*/}
        l.unlock();
    }

    void consume() {
        /*something specular*/
    }
};

int main(int argc, char* argv[]) {

    monitorTh* monitor = new monitorTh();
    char prodotto[32] = "oggetto";

    std::thread producer([&]() {
        monitor->produce(prodotto);
    });

    std::thread consumer([&]() {
        monitor->consume();
    });

    producer.join();
    consumer.join();
}

4 个答案:

答案 0 :(得分:36)

std::unique_lock使用RAII模式。

如果要锁定互斥锁,可以创建类型为std::unique_lock的局部变量,并将互斥锁作为参数传递。当构造unique_lock时,它将锁定互斥锁,并且它将被破坏,它将解锁互斥锁。更重要的是:如果抛出异常,则会调用std::unique_lock析构函数 ,因此将解锁互斥锁。

示例:

#include<mutex>
int some_shared_var=0;

int func() {
    int a = 3;
    { //Critical section
        std::unique_lock<std::mutex> lock(my_mutex);
        some_shared_var += a;
    } //End of critical section
}        

答案 1 :(得分:6)

std::unique_lock<std::mutex>持有对单独的std::mutex对象的锁定。通过在构造函数中传递锁对象,可以将锁对象与互斥锁相关联。除非您另行指定,否则将立即锁定互斥锁。如果锁定对象在销毁时保持锁定,那么析构函数将释放锁定。通常,std::unique_lock<std::mutex>对象将是一个局部变量,在您希望获取锁定的位置声明。

在您的情况下,produce()函数可以这样写:

void produce(char* elemProd) {
    std::unique_lock<std::mutex> lk(m); // lock the mutex
    while (/*already_present_element*/) { // condition variable waits may wake spuriously
        waitP.wait(lk);
    }
    {/*produce element*/}
    // lk releases the lock when it is destroyed
}

请注意,我已将if替换为while,以说明来自wait()来电的虚假提醒。

答案 2 :(得分:6)

使用条件变量的更详细的示例代码:

#include<mutex>
std::mutex(mu); //Global variable or place within class
std::condition_variable condition; //A signal that can be used to communicate between functions

auto MyFunction()->void
{
  std::unique_lock<mutex> lock(mu);
  //Do Stuff
  lock.unlock(); //Unlock the mutex
  condition.notify_one(); //Notify MyOtherFunction that this is done
}

auto MyOtherFunction()->void
{
   std::unique_lock<mutex> lock(mu);
   condition.wait(lock) //Wait for MyFunction to finish, a lambda can be passed also to protects against spurious wake up e.g (lock,[](){return *some condition*})
   lock.unlock();
}

答案 3 :(得分:-5)

在这种情况下,我认为你需要做的就是:

m.lock();
// Critical section code
m.unlock();