Question

我想查找按月分组的每个用户的帖子数。我目前正在使用INT（10）无符号来存储帖子的日期。

这会是一个超级快速的方法吗？

CREATE TABLE IF NOT EXISTS `media` (
  `pid` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `class` tinyint(1) NOT NULL DEFAULT '1',
  `date_class_changed` int(10) unsigned NOT NULL,
  `title` char(5) CHARACTER SET latin1 COLLATE latin1_general_cs NOT NULL,
  `url` varchar(1024) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  `media` enum('image','video') CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  `thumb` varchar(255) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  `description` varchar(140) COLLATE utf8_unicode_ci NOT NULL,
  `username` varchar(16) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  `date` int(10) unsigned NOT NULL,
  `file` varchar(1024) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  `hash` char(32) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  `hashtag` text CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  `meta` varchar(255) CHARACTER SET latin1 COLLATE latin1_general_ci NOT NULL,
  `ip` int(10) unsigned NOT NULL,
  `kind` tinyint(1) unsigned NOT NULL DEFAULT '0',
  PRIMARY KEY (`pid`),
  UNIQUE KEY `title` (`title`),
  KEY `hash` (`hash`),
  KEY `class_date` (`class`,`date_class_changed`),
  KEY `username` (`username`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=1022724 ;

这是表，我在谈论，我想显示每个mont的每个用户的帖子数量，例如：2012年9月，用户X，N个帖子等。

我在@fthiella的帮助后使用的查询是：

SELECT
    DATE_FORMAT(FROM_UNIXTIME(`date`), '%Y-%m') as YearMonth, username, COUNT(*) as Posts
FROM
  media
WHERE username = 'foobar'
GROUP BY 1
ORDER BY 1 DESC

感谢上帝，它足够快，现在我会尝试优化，以防它没有使用索引，但现在有近1M的记录表现良好。欢呼声。

Answer 1

SELECT
    DATE_FORMAT(FROM_UNIXTIME(`date`), '%Y-%m') as YearMonth,
    username,
    COUNT(*) as Posts
FROM
  media
GROUP BY
    DATE_FORMAT(FROM_UNIXTIME(`date`), '%Y-%m') as YearMonth,
    username

查找按月分组的用户的帖子，unixtime

1 个答案: