我需要每天在playframework2.0.4中执行一段代码,当我尝试使用类扩展GlobalSettings时它可以工作。但它适用于每个请求的实例。我希望它在服务器启动时有效并且每天都有一次工作。
package controllers;
import java.util.concurrent.TimeUnit;
import akka.util.Duration;
import play.Application;
import play.GlobalSettings;
import play.libs.Akka;
public class ParserJobApp extends GlobalSettings{
@Override
public void onStart(Application app) {
Akka.system().scheduler().schedule(Duration.create(0, TimeUnit.MILLISECONDS),Duration.create(6, TimeUnit.SECONDS), new Runnable() {
@Override
public void run() {
System.out.println("AAA --- "+System.currentTimeMillis());
}
});
}
}
这是我的控制器开始上面的课程
public class Application extends Controller {
public static Result index() {
ParserJobApp pr=new ParserJobApp();
pr.onStart(null);
System.out.println("sfsdfsdf");
return ok(index.render("Your new "));
}
}
答案 0 :(得分:24)
调度程序任务应仅放在Global类中。创建两个任务,仅在initialDelay
= 0毫秒时首先安排一次。
对于第二个任务,您需要使用常用日期/时间类计算当前DateTime和下一个计划发生之间的秒数(即明天8:00),然后将此差异设置为initialDelay
和同时将frequency
设置为24小时。
结果,它将从应用程序启动开始,并将在每个必需的时间安排执行任务。
修改强>
有完整的示例,(保存/编辑课程:/app/Global.java
):
import akka.util.Duration;
import org.joda.time.DateTime;
import org.joda.time.Seconds;
import play.Application;
import play.GlobalSettings;
import play.Logger;
import play.libs.Akka;
import java.util.concurrent.TimeUnit;
public class Global extends GlobalSettings {
@Override
public void onStart(Application application) {
Akka.system().scheduler().scheduleOnce(
Duration.create(0, TimeUnit.MILLISECONDS),
new Runnable() {
@Override
public void run() {
Logger.info("ON START --- " + System.currentTimeMillis());
}
}
);
Akka.system().scheduler().schedule(
Duration.create(nextExecutionInSeconds(8, 0), TimeUnit.SECONDS),
Duration.create(24, TimeUnit.HOURS),
new Runnable() {
@Override
public void run() {
Logger.info("EVERY DAY AT 8:00 --- " + System.currentTimeMillis());
}
}
);
}
public static int nextExecutionInSeconds(int hour, int minute){
return Seconds.secondsBetween(
new DateTime(),
nextExecution(hour, minute)
).getSeconds();
}
public static DateTime nextExecution(int hour, int minute){
DateTime next = new DateTime()
.withHourOfDay(hour)
.withMinuteOfHour(minute)
.withSecondOfMinute(0)
.withMillisOfSecond(0);
return (next.isBeforeNow())
? next.plusHours(24)
: next;
}
}
答案 1 :(得分:16)
这是我的解决方案,它更轻,支持用于调度的cron表达式。在此示例中,调度程序将在每天上午10:00运行。
关注全球课程:
private Cancellable scheduler;
@Override
public void onStart(Application application) {
super.onStart(application);
schedule();
}
@Override
public void onStop(Application application) {
//Stop the scheduler
if (scheduler != null) {
scheduler.cancel();
}
}
private void schedule() {
try {
CronExpression e = new CronExpression("0 00 10 ? * *");
Date nextValidTimeAfter = e.getNextValidTimeAfter(new Date());
FiniteDuration d = Duration.create(
nextValidTimeAfter.getTime() - System.currentTimeMillis(),
TimeUnit.MILLISECONDS);
Logger.debug("Scheduling to run at "+nextValidTimeAfter);
scheduler = Akka.system().scheduler().scheduleOnce(d, new Runnable() {
@Override
public void run() {
Logger.debug("Ruuning scheduler");
//Do your tasks here
schedule(); //Schedule for next time
}
}, Akka.system().dispatcher());
} catch (Exception e) {
Logger.error("", e);
}
}
答案 2 :(得分:4)
这可以使用Global Class完成,并且可以使用onstart方法。 https://www.playframework.com/documentation/2.5.x/JavaGlobal
以下代码以10分钟间隔打印JVM统计信息。可以配置持续时间以满足需要。
下面给出编码的抽象视图。希望这个帮助
public class Global extends GlobalSettings {
private Cancellable scheduler;
@Override
public void onStart(Application application) {
int timeDelayFromAppStartToLogFirstLogInMs = 0;
int timeGapBetweenMemoryLogsInMinutes = 10;
scheduler = Akka.system().scheduler().schedule(Duration.create(timeDelayFromAppStartToLogFirstLogInMs, TimeUnit.MILLISECONDS),
Duration.create(timeGapBetweenMemoryLogsInMinutes, TimeUnit.MINUTES),
new Runnable() {
@Override
public void run() {
System.out.println("Cron Job");
// Call a function (to print JVM stats)
}
},
Akka.system().dispatcher());
super.onStart(application);
}
@Override
public void onStop(Application app) {
scheduler.cancel();
super.onStop(app);
}
}