如何修复无法打开wav设备LumiSoft.Net?

时间:2013-02-05 07:10:53

标签: c# .net voice lumisoft

我将此代码用于开放波设备,并获得此异常“无法打开波设备”。当我重置计算机时它不会出现异常,并且第一次运行程序时它没关系,但之后每次运行以例外结束。

public WaveOut(WavOutDevice outputDevice,int samplesPerSec,int bitsPerSample,int channels)
        {
            if(outputDevice == null){
                throw new ArgumentNullException("outputDevice");
            }
            if(samplesPerSec < 8000){
                throw new ArgumentException("Argument 'samplesPerSec' value must be >= 8000.");
            }
            if(bitsPerSample < 8){
                throw new ArgumentException("Argument 'bitsPerSample' value must be >= 8.");
            }
            if(channels < 1){
                throw new ArgumentException("Argument 'channels' value must be >= 1.");
            }

            m_pOutDevice    = outputDevice;
            m_SamplesPerSec = samplesPerSec;
            m_BitsPerSample = bitsPerSample;
            m_Channels      = channels;
            m_BlockSize     = m_Channels * (m_BitsPerSample / 8);
            m_pPlayItems    = new List<PlayItem>();

            // Try to open wav device.            
            WAVEFORMATEX format = new WAVEFORMATEX();
            format.wFormatTag      = WavFormat.PCM;
            format.nChannels       = (ushort)m_Channels;
            format.nSamplesPerSec  = (uint)samplesPerSec;                        
            format.nAvgBytesPerSec = (uint)(m_SamplesPerSec * m_Channels * (m_BitsPerSample / 8));
            format.nBlockAlign     = (ushort)m_BlockSize;
            format.wBitsPerSample  = (ushort)m_BitsPerSample;
            format.cbSize          = 0; 
            // We must delegate reference, otherwise GC will collect it.
            m_pWaveOutProc = new waveOutProc(this.OnWaveOutProc);
            int result = WavMethods.waveOutOpen(out m_pWavDevHandle,m_pOutDevice.Index,format,m_pWaveOutProc,0,WavConstants.CALLBACK_FUNCTION);



            if(result != MMSYSERR.NOERROR){
                throw new Exception("Failed to open wav device, error: " + result.ToString() + ".");
            }
        }

1 个答案:

答案 0 :(得分:-1)

Altough我对c#中的wav设备没什么经验,我认为你的问题与程序关闭时不关闭设备有关。

你需要像

这样的电话
WavMethods.waveOutClose(m_pWavDevHandle);
在你的应用程序退出之前的某个地方(如果waveOutoOpen调用失败,显然不需要它)