我需要帮助;看起来很简单,但我无法弄清楚。
我的代码:
public DataTable GetUserAssociatedModules(string UserEmail)
{
// retrieve module titles from Module table to be passed to ddlModules in Student.Master
try
{
SqlCommand getModules = new SqlCommand("GetUserAssociatedModules", con);
getModules.Parameters.AddWithValue("@userEmail", UserEmail);
SqlDataReader dr;
dr = getModules.ExecuteReader();
//DataTable dt = new DataTable();
dt.Columns.Add("moduleTitle");
dt.Load(dr);
return dt;
}
catch (Exception ex)
{
HttpContext.Current.Response.Write("Exception: " + ex.Message + ", CourseDAO.GetModules()");
return null;
}
finally
{
// close database connection
if (con != null)
{
con.Close();
}
}
}
我一直有例外:
程序或功能' GetUserAssociatedModules'需要参数' @ userEmail',这是未提供的。
我在UserEmail
上放了一块手表;它应该从UI中传递值,但是datareader保持为空...
我检查了我的SQL;它执行正常。
我进行了双重和三重检查,以确保代码中调用的存储过程名称与数据库中的过程匹配,并且代码中的参数名称与过程中的参数名称匹配...
程序......
ALTER PROCEDURE [dbo].[GetUserAssociatedModules]
@userEmail nvarchar(MAX)
AS
BEGIN
SELECT
[dbo].[Module].[moduleId],[moduleTitle]
FROM
[dbo].[Module]
INNER JOIN
[dbo].[ModuleUser] ON [dbo].[Module].[moduleId] = [dbo].[ModuleUser].[moduleId]
WHERE
[dbo].[ModuleUser].[userId] = (SELECT [userId]
FROM [dbo].[User]
WHERE [eMail] = @userEmail)
ORDER BY
[moduleTitle] ASC
END
答案 0 :(得分:5)
您缺少打开连接:
<强> conn.Open(); 强>
或者没有指定这一行:
sqlCommand.CommandType = CommandType.StoredProcedure;
public DataTable GetUserAssociatedModules(string UserEmail)
{
var dt = new DataTable();
string connString = AppConfigurationManager.GetAppSetting("ConnectionString",IsTest,IsQA, IsProd);
using (var conn = new SqlConnection(connString))
{
conn.Open();
using (var sqlCommand = new SqlCommand("GetUserAssociatedModules", conn))
{
sqlCommand.CommandType = CommandType.StoredProcedure;
sqlCommand.Parameters.AddWithValue("@userEmail", userEmail);
SqlDataReader dr = null;
DataSet ds = new DataSet();
try
{
dr = sqlCommand.ExecuteReader();
dt = new DataTable("DatatTable_GetUserAssociatedModules");
ds.Tables.Add(dt);
ds.Load(dr, LoadOption.OverwriteChanges, dt);
}
catch (SqlException ex)
{
LogExceptions(ex, new List<Param> { new Param { Name = "userEmail", Value = userEmail} });
}
catch (Exception ex)
{
LogExceptions(ex, new List<Param> { new Param { Name = "userEmail", Value = userEmail} });
}
finally
{
}
}
}
return dt;
}