Question

我想使用两种网络路由之一连接到服务器。怎么会这样做？我用谷歌搜索了很多，常见的答案是摆弄路由表，但是由于目的地只有一个IP地址，这无济于事。大多数示例都包含一个带有单个网卡的客户端和一个带有多个NIC的服务器，但在这种情况下则相反。

ForceBindIP应用程序似乎能够提供此类功能，所以我想它一定是可能的。

             +----->-------+
192.168.1.3  |      B      |          192.168.1.4
      +--------+      +--------+      +--------+
      | Client |      | Switch |-->---| Server |
      +--------+      +--------+      +--------+
192.168.1.2  |      A      |
             +----->-------+

我很可能会使用C ++和winsock来做到这一点。我需要能够随意打开给定路由上的连接（即不得静态绑定到特定路由）。我将使用普通的'TCP / IP。

编辑：Windows 7客户端

Answer 1

在致电192.168.1.3，192.168.1.2或connect()之前，使用bind()功能将套接字绑定到ConnectEx()或WSAConnect()。这告诉套接字使用哪个特定接口进行传出连接。例如：

SOCKET s = socket(AF_INET, SOCK_STREAM, IPPROTO_TCP);

sockaddr_in localaddr = {0};
localaddr.sin_family = AF_INET;
localaddr.sin_addr.s_addr = inet_addr("192.168.1.3");
bind(s, (sockaddr*)&localaddr, sizeof(localaddr));

sockaddr_in remoteaddr = {0};
remoteaddr.sin_family = AF_INET;
remoteaddr.sin_addr.s_addr = inet_addr("192.168.1.4");
remoteaddr.sin_port = 12345; // whatever the server is listening on
connect(s, (sockaddr*)&remoteaddr, sizeof(remoteaddr));

可替换地：

addrinfo localhints = {0};
localhints.ai_flags = AI_NUMERICHOST | AI_NUMERICSERV;
localhints.ai_family = AF_INET;
localhints.ai_socktype = SOCK_STREAM;
localhints.ai_protocol = IPPROTO_TCP;

addrinfo *localaddr = NULL;
getaddrinfo("192.168.1.3", "0", &localhints, &localaddr);
bind(s, localaddr->ai_addr, localaddr->ai_addrlen);
freeaddrinfo(localaddr);

addrinfo remotehints = {0};
remotehints.ai_flags = AI_NUMERICHOST | AI_NUMERICSERV;
remotehints.ai_family = AF_INET;
remotehints.ai_socktype = SOCK_STREAM;
remotehints.ai_protocol = IPPROTO_TCP;

addrinfo *remoteaddr = NULL;
getaddrinfo("192.168.1.4", "12345", &remotehints, &remoteaddr);
connect(s, remoteaddr->ai_addr, remoteaddr->ai_addrlen);
freeaddrinfo(remoteaddr);

特定接口上的TCP / IP连接

1 个答案: