我正在尝试在我的网站上实施一个只有两个级别的评论系统,例如,您将获得主要评论并回复该评论,但它不会更进一步:
main comment 1
(sub_comment1)
(sub_comment2)
main comment 2
(sub_comment1)
(sub_comment2)
(sub_comment2)
等...
有意义吗?
我在codeigniter中创建网站,但我认为基本的php解决方案可以。
我的数据库表中的每一行都有一个id和一个parent_id,如果父id为0,那么它是一个主注释,如果它是一个子注释,它将在parent_id中具有其父注释的id。
如何以正确的顺序输入带有父级和子级注释的二维数组。
我当前的代码是这样的:控制器:
function status_comments($id){
$this->load->model('status_model');//load the status model
$this->load->model('comment_model');//load the comment model
$status = $this->status_model->get_entry_and_category($id);
$comments = $this->comment_model->get_comments($id);
if($status !== false) {
if($comments !== false) {
foreach($comments as $comment){
if($comment->reply_id == 0){
$comment =
}
}
$content_data['comments'] = $comments;
}
$content_data['status'] = $status;
$data['content'] = $this->load->view('status_view', $content_data, TRUE);
$data['title'] = $status->title.' - High Value Status';
$data['page_title'] = $status->title;//The page H1 tag
$this->load->view('home', $data);
}
else
{
$this->session->set_flashdata('invalid', '<p class="rejectionalert"><span>The status you tried to view does not exist.</span></p>');
redirect('home');
}
}
模型功能:
//Gets comments associated with an individual status
function get_comments($status_id, $offset=null, $limit=null)
{
$this->db->select('id, comment, nickname, created, reply_id');
$this->db->from('comments');
$this->db->where('active', 1);
$this->db->where('status_id', $status_id);
$query = $this->db->get();
if ($query->num_rows() > 0) {
return $query->result();
}
return false;
}
答案 0 :(得分:0)
这可以使用但它使用多个查询,模型:
function get_comments($status_id, $limit=NULL, $offset=NULL)
{
$this->db->where(array('status_id' => $status_id, 'reply_id' => 0));
$query = $this->db->get('comments', $limit, $offset);
$parents = $query->result_array();
$comments = array();
foreach($parents as $key => $comment)
{
array_push($comments, $comment);
$this->db->order_by('created', 'ASC');
$this->db->where(array('status_id' => $status_id, 'reply_id' => $comment['id']));
$comments = array_merge($comments, $this->db->get('comments')->result_array());
}
return $comments;
}
我认为对所有评论进行一次查询,通过他们的id将它们索引到一个数组中,并再次迭代它们以找到他们的孩子会更有效。我还不知道如何实现它?