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Question

我有一个EditText视图，我希望它将用户的输入格式化为电话号码格式。例如，当用户键入1234567890时，只要输入前3个数字，EditText视图就会动态显示为“（123）456-7890”。

我在OnCreate中尝试了以下内容，但它似乎没有为我做任何事......

EditText ET = (EditText) findViewById(R.id.add_number);
ET.addTextChangedListener(new PhoneNumberFormattingTextWatcher());

如何让用户输入以电话号码格式显示？

Answer 1

使用此代码，您可以制作自定义TextWatcher并制作所需的任何格式：

ET.addTextChangedListener(new PhoneNumberFormattingTextWatcher() {
        //we need to know if the user is erasing or inputing some new character
        private boolean backspacingFlag = false;
        //we need to block the :afterTextChanges method to be called again after we just replaced the EditText text
        private boolean editedFlag = false;
        //we need to mark the cursor position and restore it after the edition
        private int cursorComplement;

        @Override
        public void beforeTextChanged(CharSequence s, int start, int count, int after) {
            //we store the cursor local relative to the end of the string in the EditText before the edition
            cursorComplement = s.length()-ET.getSelectionStart();
            //we check if the user ir inputing or erasing a character
            if (count > after) {
                backspacingFlag = true;
            } else {
                backspacingFlag = false;
            }
        }

        @Override
        public void onTextChanged(CharSequence s, int start, int before, int count) {
            // nothing to do here =D
        }

        @Override
        public void afterTextChanged(Editable s) {
            String string = s.toString();
            //what matters are the phone digits beneath the mask, so we always work with a raw string with only digits
            String phone = string.replaceAll("[^\\d]", "");

            //if the text was just edited, :afterTextChanged is called another time... so we need to verify the flag of edition
            //if the flag is false, this is a original user-typed entry. so we go on and do some magic
            if (!editedFlag) {

                //we start verifying the worst case, many characters mask need to be added
                //example: 999999999 <- 6+ digits already typed
                // masked: (999) 999-999
                if (phone.length() >= 6 && !backspacingFlag) {
                    //we will edit. next call on this textWatcher will be ignored
                    editedFlag = true;
                    //here is the core. we substring the raw digits and add the mask as convenient
                    String ans = "(" + phone.substring(0, 3) + ") " + phone.substring(3,6) + "-" + phone.substring(6);
                    ET.setText(ans);
                    //we deliver the cursor to its original position relative to the end of the string
                    ET.setSelection(ET.getText().length()-cursorComplement);

                //we end at the most simple case, when just one character mask is needed
                //example: 99999 <- 3+ digits already typed
                // masked: (999) 99
                } else if (phone.length() >= 3 && !backspacingFlag) {
                    editedFlag = true;
                    String ans = "(" +phone.substring(0, 3) + ") " + phone.substring(3);
                    ET.setText(ans);
                    ET.setSelection(ET.getText().length()-cursorComplement);
                }
            // We just edited the field, ignoring this cicle of the watcher and getting ready for the next
            } else {
                editedFlag = false;
            }
        }
    });

确保将XML中的EditText Lenght限制为14个字符

<EditText
    android:id="@+id/editText_phone"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:inputType="phone"
    android:lines="1"
    android:maxLength="14"/>

Answer 2

步骤1：这里是XML文件中输入字段的代码。

 <EditText
    android:id="@+id/editText_phone"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:inputType="phone"
    android:lines="1"
    android:maxLength="14"/>

第2步：这是添加到MainFile.java

的代码

 phoneNo = (EditText)findViewById(R.id.editText_phone);
 phoneNo.addTextChangedListener(new PhoneNumberFormattingTextWatcher());

输出：它会给你一个像（123）456-7890

这样的数字

Answer 3

我做了一些事情的组合，我将输入类型修改为手机，然后我使用正则表达式删除所有非数字字符：phonenumber = phonenumber.replaceAll（“\ D”，“”）;

Answer 4

试试这个

PhoneNumberFormattingTextWatcher（）方法无法正常工作我尝试分配最后我得到解决方案

在您的xml文件中粘贴此

<EditText
android:id="@+id/editTextId"
android:layout_height="wrap_content"
android:layout_width="match_parent"
android:inputType="phone"
android:digits="0123456789+" />

粘贴了这个

final EditText editText = (EditText) findViewById(R.id.editTextId);
editText.addTextChangedListener(new TextWatcher()
{
    @Override
    public void onTextChanged(CharSequence s, int start, int before, int count)
    {
        // TODO Auto-generated method stub
    }

    @Override
    public void beforeTextChanged(CharSequence s, int start, int count, int after)
    {
        // TODO Auto-generated method stub
    }
    @Override
    public void afterTextChanged(Editable s)
    {
        String text = editText.getText().toString();
        int  textLength = editText.getText().length();
        if (text.endsWith("-") || text.endsWith(" ") || text.endsWith(" "))
            return;
        if (textLength == 1) {
            if (!text.contains("("))
            {
                editText.setText(new StringBuilder(text).insert(text.length() - 1, "(").toString());
                editText.setSelection(editText.getText().length());
            }
        }
        else if (textLength == 5)
        {
            if (!text.contains(")"))
            {
                editText.setText(new StringBuilder(text).insert(text.length() - 1, ")").toString());
                editText.setSelection(editText.getText().length());
            }
        }
        else if (textLength == 6)
        {
            editText.setText(new StringBuilder(text).insert(text.length() - 1, " ").toString());
            editText.setSelection(editText.getText().length());
        }
        else if (textLength == 10)
        {
            if (!text.contains("-"))
            {
                editText.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
                editText.setSelection(editText.getText().length());
            }
        }
        else if (textLength == 15)
        {
            if (text.contains("-"))
            {
                editText.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
                editText.setSelection(editText.getText().length());
            }
        }
        else if (textLength == 18)
        {
            if (text.contains("-"))
            {
                editText.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
                editText.setSelection(editText.getText().length());
            }
        }
    }
});

<强>输出： -

Answer 5

在您的布局中，将输入模式设置为“手机”

http://developer.android.com/reference/android/widget/TextView.html#attr_android:inputMethod http://developer.android.com/reference/android/text/InputType.html#TYPE_CLASS_PHONE

<EditText
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:inputType="phone" />

如果这不太适合您的需要，请在EditText中添加一个监听器，并在每次击键时手动设置文本格式。

    editText.setOnKeyListener(new OnKeyListener() {

        @Override
        public boolean onKey(View v, int keyCode, KeyEvent event) {
            if (event.getAction() == KeyEvent.ACTION_UP) {
                // format your EditText here
            }
            return false;
        }
    });

Answer 6

在Java代码中，您可以使用

yourEditText.setInputType(InputTytpe.TYPE_CLASS_PHONE)

或在你的xml中

android:inputType="phone"

Java

XML

Answer 7

请在下面找到代码：
我使用TextWatcher界面将输入的电话号码格式化为（XXX）XXX-XXXX动态。

UsPhoneNumberFormatter addLineNumberFormatter = new UsPhoneNumberFormatter(edittxtPhoneNo);
edittxtPhoneNo.addTextChangedListener(addLineNumberFormatter);  


public class UsPhoneNumberFormatter implements TextWatcher {
    private EditText etMobile;

    public UsPhoneNumberFormatter(EditText edt) {
        etMobile = edt;
    }

    @Override
    public void beforeTextChanged(CharSequence charSequence, int i, int i1, int i2) {
    }

    @Override
    public void onTextChanged(CharSequence charSequence, int i, int i1, int i2) {
        String text = etMobile.getText().toString();
        int textlength = etMobile.getText().length();

        if (text.endsWith(" "))
            return;

        if (textlength == 1) {
            if (!text.contains("(")) {
                etMobile.setText(new StringBuilder(text).insert(text.length() - 1, "(").toString());
                etMobile.setSelection(etMobile.getText().length());
            }
        } else if (textlength == 5) {
            if (!text.contains(")")) {
                etMobile.setText(new StringBuilder(text).insert(text.length() - 1, ")").toString());
                etMobile.setSelection(etMobile.getText().length());
            }
        } else if (textlength == 6) {
            if (!text.contains(" ")) {
                etMobile.setText(new StringBuilder(text).insert(text.length() - 1, " ").toString());
                etMobile.setSelection(etMobile.getText().length());
            }
        } else if (textlength == 10) {
            if (!text.contains("-")) {
                etMobile.setText(new StringBuilder(text).insert(text.length() - 1, "-").toString());
                etMobile.setSelection(etMobile.getText().length());
            }
        }
    }

    @Override
    public void afterTextChanged(Editable editable) {
    }
}

Answer 8

您可以使用JQuery validate（onkeyup事件）执行此操作，因此您可以在键入时进行动态格式化（在那里思考经验） - 或者您可以使用诸如RAZOR或KnockoutJS之类的MVVM库（当它们退出时）该领域）。

您要执行的操作的示例包括JQuery Validate文档站点以及淘汰JS站点。

格式化EditText视图以获取电话号码

8 个答案:

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