Question

#!/usr/bin/perl

use strict;
use warnings;
my $username = '$ARGV[0]';
my $password = '$ARGV[1]';
use Net::SSH::Expect;
my $ssh = Net::SSH::Expect-> new (
        host => "10.38.228.230",
        password => "lsxid4",
        user => "root",
        raw_pty => 1,
        timeout => 10,
        log_file => "log_file"  
);

my $login_output=$ssh->login();
if ( $login_output =~ /Last/ )
   {
   print "The login for ROOT was successful, Let's see if we can change the password \n";
   $ssh->send("passwd $username");
   $ssh->waitfor ('password:\s*', 10) or die "Where is the first password prompt??";
   $ssh->send("$password");
   $ssh->waitfor ('password:\s*', 10) or die "Where is the Second password promp??";
   $ssh->send("$password");
   $ssh->waitfor('passwd:\s*',5);
   print "The password for $username has been changed successfully \n";
   }
   else
   {
      die "The log in for ROOT was _not_ successful.\n";
   }

我试图通过以root身份登录主机来改变远程主机上的用户密码但如果我在其工作的代码中提供硬编码值，$username, $password似乎不会取值。

在命令行上运行如下：

bash-3.00# ./test6.pl rak xyz12   
The login for ROOT was successful, Let's see if we can change the password
Where is the first password prompt?? at ./test6.pl line 22.
bash-3.00#

如何远程更改用户密码

Answer 1

问题是你在这里使用单引号：

my $username = '$ARGV[0]';
my $password = '$ARGV[1]';

首先，没有必要以这种方式引用变量。其次，当使用单引号时，内容不是内插的，它只是文字字符串$ARGV[0]。

这应该是：

my $username = $ARGV[0];
my $password = $ARGV[1];

但更优雅的解决方案是：

my ($username, $password) = @ARGV;

利用在列表上下文中进行分配的可能性。或者：

my $username = shift;
my $password = shift;

shift将隐式地将参数从@ARGV或@_移开，具体取决于上下文（无论您是否在子例程内）。

使用Net :: SSH :: Expect远程更改用户密码;

1 个答案: