Question

我正在尝试从服务器端mysql数据创建一个websql表。下面有效，但我想知道有更好的方法吗？

PHP脚本，其中包含javascript。

<?php
include_once("../../inc/config.inc.php");
//access_control();
$query = "SELECT id, productname, price FROM `products`";
$result = $mysqli->query($query) or die('error');
?>
<script>
var db = window.openDatabase("test", "1.0", "test local", 2 * 1024 * 1024);
window.onload = function() {
  if (!window.openDatabase) {
status("Database not supported");
return;
}
db.transaction(function(tx) {
 //tx.executeSql("drop table if exists products");
tx.executeSql("create table if not exists products ("
  + "id integer primary key,"
  + "name text,"
  + "price integer"
  + ")",null,null, logger);
  <php?
  $i=1;
  if($result->num_rows > 0) {
    while($row = $result->fetch_assoc()) {
echo "tx.executeSql(\"INSERT INTO products(id, name, price) VALUES ('".$row['id']."','".$row['productname']."','".$row['price']."');\");\n";
    }
}
?>
  });

db.transaction();

</script>

php脚本的

输出只提供javascript。

<script>
var db = window.openDatabase("test", "1.0", "test local", 2 * 1024 * 1024);
window.onload = function() {
if (!window.openDatabase) {
status("Database not supported");
return;
}
db.transaction(function(tx) {
tx.executeSql("drop table if exists products");
tx.executeSql("create table if not exists products ("
  + "id integer primary key,"
  + "name text,"
  + "price integer"
  + ")",null,null, logger);
tx.executeSql("INSERT INTO products(id, name, price) VALUES ('12','bla bla ','3.99');");
tx.executeSql("INSERT INTO products(id, name, price) VALUES ('13','BO BO','3.40');");

});

db.transaction();
</script>

mysql表数据到websql表数据

0 个答案: