Question

我尝试过各种命令，比如

driver.switch_to_window("_blank")

或

driver.switch_to_window(None)

但这些都没有奏效。应该怎么做？感谢。

Answer 1

经过大量的谷歌搜索后，我发现在Firefox中对我有用的东西很简单（优雅，可能？）几乎可笑。这是：

>>> from selenium import webdriver
>>> driver = webdriver.Firefox()
>>> driver.execute_script("window.open('');")  <--- JAVASCRIPT!

Answer 2

看看this question。好像图书馆不支持标签管理atm。

但是排名第二的答案确实提供了解决方案。我想你可以轻松地将它翻译成Python。

Answer 3

我用这种方式解决了问题：

a_elem = driver.find_element_by_link_text("Link with _blank")
self.driver.get(a_elem.get_attribute('href'))

Answer 4

我遇到了同样的问题，我对我找到的其他解决方案并不满意，所以我做了一个上下文管理器来处理。这允许：

with link_in_new_window(driver, link_element):
    driver.foo()  # this is in the new window opened from the link
driver.foo()  # this is back in the original window

..我觉得很方便。

from contextlib import contextmanager
from selenium.common import exceptions
from selenium.webdriver.common.action_chains import ActionChains
from selenium.webdriver.common.keys import Keys

# Fundamentally, this shift-clicks to open a new window, and
# hits ctrl-w to close it when done, using ActionChains.
@contextmanager
def link_in_new_window(driver, element):
    """Open a clickable element in a new window for this context

    This opens a clickable element in a new window, and switches
    `driver` to that window for the duration of the context.  
    The window is closed afterward, and the driver switched back
    to the original window.

    If the 'as' clause is used, the handle of the parent (original)
    window is provided as the value.

    Selenium doesn't provide a useful interface to firefox's tabs
    due to some technical complications, so we use new windows
    instead of new tabs. The memory hit isn't too significant.

    :type driver: selenium.webdriver.Firefox
    :type element: selenium.webdriver.remote.webelement.WebElement
    :returns: Parent's Window Handle
    """

    known_handles = set(driver.window_handles)
    original_handle = driver.current_window_handle
    action = ActionChains(driver)
    # Open link in new window (shift-click element)
    # Sometimes, shift would be ignored. move_to_element helped.
    action.move_to_element(element)
        .key_down(Keys.SHIFT)
        .click(element)
        .key_up(Keys.SHIFT)
        .perform()

    # Find the new window handle.  ..anyone know a better way?
    timeout = time.time() + 10
    new_handles = set(driver.window_handles) - known_handles
    while time.time() < timeout and not new_handles:
        new_handles = set(driver.window_handles) - known_handles
        time.sleep(0.5)
    if not new_handles or len(new_handles) != 1:
        msg = "Expected one handle, found {}"
        raise RuntimeError(msg.format(len(new_handles)), new_handles)
    new_handle = new_handles.pop()
    driver.switch_to.window(new_handle)
    try:
        # User code will be executed here
        yield original_handle
    finally:
        # close window, if it still exists (ctrl-w)
        try:
            driver.switch_to.window(new_handle)
            action = ActionChains(driver)
            action.key_down(Keys.CONTROL).send_keys('w').perform()
        except exceptions.NoSuchWindowException:
            pass
        # in any case, switch back to the original window
        driver.switch_to.window(original_handle)

如何在webdriver（Python）中打开一个新窗口或选项卡？

4 个答案: