我有点想知道该怎么做,但我无法理解。该计划需要能够获得学生姓名和三个考试成绩,然后从三个分数中获得平均分数(百分比)。之后,您需要将分数(百分比)转换为成绩。
修改 如何删除成绩中间的空格和“%”?
评分等级:
input ('Please press "Enter" to begin')
while True:
import math
studentName = str(input('Enter your Name: '))
firstScore = int(float(input('First test score: ').replace('%', '')))
secondScore = int(float(input('Second test score: ').replace('%', '')))
thirdScore = int(float(input('Third test score: ').replace('%', '')))
scoreAvg = (firstScore + secondScore + thirdScore) / 3
def grade():
if scoreAvg >= 93 and <= 100:
return 'A'
if scoreAvg <= 92.9 and >= 89:
return 'A-'
if scoreAvg <= 88.9 and >= 87:
return 'B+'
if scoreAvg <= 86.9 and >= 83:
return 'B'
if scoreAvg <= 82.9 and >= 79:
return 'B-'
if scoreAvg <= 78.9 and >= 77:
return 'C+'
if scoreAvg <= 76.9 and >= 73:
return 'C'
if scoreAvg <= 72.9 and >= 69:
return 'C-'
if scoreAvg <= 68.9 and >= 67:
return 'D+'
if scoreAvg <= 66.9 and >= 60:
return 'D'
return 'F'
print(grade(scoreAvg))
print(studentName, "test score is: ",scoreAvg,'%')
endProgram = input ('Do you want to restart the program?')
if endProgram in ('no', 'No', 'NO', 'false', 'False', 'FALSE'):
break
答案 0 :(得分:3)
不确定你的问题是什么,但这里有一个更简洁的方式来获得字母等级。
>>> scores = [93, 89, 87, 83, 79, 77, 73, 69, 67, 60, 0]
>>> grades = ['A', 'A-', 'B+', 'B', 'B-', 'C+', 'C', 'C-', 'D+', 'D', 'F']
>>> grade_scores = zip(scores, grades)
>>> def gradeFor(s):
... for score, grade in grade_scores:
... if s >= score:
... return grade
>>> gradeFor(87)
B+
>>> gradeFor(89)
A-
>>> gradeFor(88)
B+
>>> gradeFor(67)
D+
>>> gradeFor(72)
C-
>>> gradeFor(40)
F
另外,你可以做到
if endProgram.lower() in ('no', 'false'):