Question

我需要有关此查询的帮助...

SELECT FIRST_NAME, LAST_NAME, test.EMAIL 
      FROM test
INNER JOIN suppression ON suppression.EMAIL = test.EMAIL
AND NOT EXISTS (select * from suppression)

我想要来自表“test”的所有记录，其中表“suppress”不包含类似的记录。

Answer 1

我个人更喜欢LEFT JOIN IS NULL方法，但这里有NOT EXISTS的替代方法：

SELECT FIRST_NAME, LAST_NAME, EMAIL 
FROM test
WHERE NOT EXISTS (SELECT * FROM suppression WHERE email = test.email)

不能真正地离开NOT IN：

SELECT FIRST_NAME, LAST_NAME, EMAIL 
FROM test
WHERE Email NOT IN (SELECT Email FROM suppression)

祝你好运。

Answer 2

使用LEFT JOIN

SELECT  a.*
FROM    test a
        LEFT JOIN suppression 
            ON suppression.EMAIL = a.EMAIL
WHERE   suppression.EMAIL IS NULL

要充分了解联接知识，请访问以下链接：

Visual Representation of SQL Joins

选择查询，其他表不包含类似记录

2 个答案: