Question

我对此感到困惑......我正在使用以下代码将记录加载到表单中进行编辑。记录加载到字段等中。我单击提交并且记录不会重新加载。如果我在url中使用edit_link.php？link_pk = 50，则不会加载记录。如果我将值更改为未编辑的记录，则会将其加载到表单中，但如果我编辑该记录，则会发生同样的情况。数据库中的数据与编辑之前的数据完全相同（即我在提交之前没有更改任何内容）：

$link_pk = $_GET['link_pk'];
$author_pk = $_GET['author_pk'];

$title = $_POST['title'];
$url = mysql_real_escape_string($_POST['url']);
$url_for_link = $_POST['url'];
$alt = $_POST['alt'];
$credit = $_POST['credit'];
$sub_discipline_fk = $_POST['sub_discipline'];
$link_category_fk = $_POST['category'];
$icon = $_POST['icon'];

$query_link = "SELECT * FROM link, sub_discipline, link_category, link_icon WHERE link.sub_discipline_fk = sub_discipline.sub_discipline_pk AND link.link_category_fk = link_category.link_category_pk AND link.link_icon_fk = link_icon.link_icon_pk AND link.link_pk = '$link_pk'";
$result_link = mysql_query($query_link, $connection) or die(mysql_error());
$row_link = mysql_fetch_assoc($result_link);


switch ($icon) {
    case '1':
        $link = mysql_real_escape_string("<a class='text' href='" . $url_for_link . "' target='_blank' alt='" . $alt . "' >" . $title . "</a>");
        break;
    case '2':
        $link = mysql_real_escape_string("<a class='video' href='" . $url_for_link . "' target='_blank' alt='" . $alt . "' >" . $title . "</a>");
        break;
    case '3':
        $link = mysql_real_escape_string("<a class='interactive' href='" . $url_for_link . "' target='_blank' alt='" . $alt . "' >" . $title . "</a>");
        break;
    case '4':
        $link = mysql_real_escape_string("<a class='microscope' href='" . $url_for_link . "' target='_blank' alt='" . $alt . "' >" . $title . "</a>");
        break;
}

if(isset($_POST['submit'])){ 
        $query = "UPDATE link SET link_title = '$title', url = '$url', link = '$link', alt = '$alt', credit = '$credit', sub_discipline_fk = '$sub_discipline_fk', updated = NOW(), updated_by = '$author_pk', link_category_fk = '$link_category_fk', link_icon_fk = '$link_icon_fk' WHERE link_pk = '$link_pk'";
        $result = mysql_query($query, $connection) or die(mysql_error());
                if($result){
                    $query_link = "SELECT * FROM link, sub_discipline, link_category, link_icon WHERE link.sub_discipline_fk = sub_discipline.sub_discipline_pk AND link.link_category_fk = link_category.link_category_pk AND link.link_icon_fk = link_icon.link_icon_pk AND link.link_pk = '$link_pk'";
$result_link = mysql_query($query_link, $connection) or die(mysql_error());
$row_link = mysql_fetch_assoc($result_link);
            $message = '- The link has been updated';
        }
}

请不要提醒我，上述内容已被删除，我知道这一点。

由于

Answer 1

愚蠢的错误......我更改了一个变量名称并且在查询中没有更改它... link_icon_fk ='$ link_icon_fk'应该是link_icon_fk ='$ icon' - 试图工作得太快......

更新查询后，记录不会加载到编辑页面

1 个答案: