在If / Switch语句中使用用户输入的字符

时间:2013-02-03 19:18:17

标签: java if-statement switch-statement

我正在学习我的第一个Java课程,并且很难完成这项任务。

作业本身很简单。我所要做的就是提示用户输入一个整数,一个字符,然后输入另一个整数。

如果输入的字符是+,则应将两个整数相加。如果输入的字符是 - ,则应减去两个整数。等...

问题是我不知道如何接受用户的字符,然后在我的If / Switch语句中使用它。

以下是我的提示:

// Prompt the user to enter an integer
    System.out.print("Please enter an integer number:");
    int int1  = input.nextInt();

// Prompt the user to enter a character
// Since I could not use characters, I am using integers to represent them.
    System.out.print("Enter 0 for +, 1 for -, 2 for /, 3 for %, and 4 for *");
    int char1 = input.nextInt();

// Prompt the user to enter another integer
    System.out.print("Please enter another integer number:");
    int int2 = input.nextInt();

以下是我的If / Switch语句:(我知道它们是多余的,但它是作业的一部分)

if (char1 == 0) {
    int ans = int1 + int2;
    System.out.println(int1 + " + " + int2 + " = " + ans);
} else if (char1 == 1) {
    int ans = int1 - int2;
    System.out.println(int1 + " - " + int2 + " = " + ans);
} else if (char1 == 2) {
    int ans = int1 / int2;
    System.out.println(int1 + " / " + int2 + " = " + ans);
} else if (char1 == 3) {
    int ans = int1 % int2;
    System.out.println(int1 + " % " + int2 + " = " + ans);
} else if (char1 == 4) {
    int ans = int1 * int2;
    System.out.println(int1 + " * " + int2 + " = " + ans);
} else
    System.out.println("Invalid operator");

int result = 0;
switch (char1) {
    case 0: result = int1 + int2;
            System.out.println(int1 + " + " + int2 + " = " + result); break;
    case 1: result = int1 - int2;
            System.out.println(int1 + " - " + int2 + " = " + result); break;
    case 2: result = int1 / int2;
            System.out.println(int1 + " / " + int2 + " = " + result); break;
    case 3: result = int1 % int2;
            System.out.println(int1 + " % " + int2 + " = " + result); break;
    case 4: result = int1 * int2;
            System.out.println(int1 + " * " + int2 + " = " + result); break;
    default: System.out.println("Invalid operator");
}

其他一切都很好。我只是想改变使用0代表+,1代表 - ,改为使用+, - ,/,%和*。

3 个答案:

答案 0 :(得分:2)

您可以将用户的操作符设为字符串字符

像这样:

 Scanner input = new Scanner(System.in);
        // Prompt the user to enter an integer
        System.out.print("Please enter an integer number:");
        int int1 = input.nextInt();

// Prompt the user to enter a character
// Since I could not use characters, I am using integers to represent them.
        System.out.print("Enter +, -,  /,  %, *");
        char char1 = input.next().charAt(0);

// Prompt the user to enter another integer
        System.out.print("Please enter another integer number:");
        int int2 = input.nextInt();

        if (char1=='+') {
            int ans = int1 + int2;
            System.out.println(int1 + " + " + int2 + " = " + ans);
        } else if (char1=='-') {
            int ans = int1 - int2;
            System.out.println(int1 + " - " + int2 + " = " + ans);
        } else if (char1=='/') {
            int ans = int1 / int2;
            System.out.println(int1 + " / " + int2 + " = " + ans);
        } else if (char1=='%') {
            int ans = int1 % int2;
            System.out.println(int1 + " % " + int2 + " = " + ans);
        } else if (char1=='*') {
            int ans = int1 * int2;
            System.out.println(int1 + " * " + int2 + " = " + ans);
        } else {
            System.out.println("Invalid operator");
        }

        int result = 0;

        switch (char1) {
            case '+':
                result = int1 + int2;
                System.out.println(int1 + " + " + int2 + " = " + result);
                break;
            case '-':
                result = int1 - int2;
                System.out.println(int1 + " - " + int2 + " = " + result);
                break;
            case '/':
                result = int1 / int2;
                System.out.println(int1 + " / " + int2 + " = " + result);
                break;
            case '%':
                result = int1 % int2;
                System.out.println(int1 + " % " + int2 + " = " + result);
                break;
            case '*':
                result = int1 * int2;
                System.out.println(int1 + " * " + int2 + " = " + result);
                break;
            default:
                System.out.println("Invalid operator");
        }

答案 1 :(得分:1)

你可以这样做:

System.out.print("Enter +, -, /, or *");
char char1 = input.nextLine().charAt(0);

nextLine将获取用户输入的全部内容,charAt获取指定索引处的字符。

因此,charAt(0)获得第一个字符。这是一个直观的解释:顶部是字符串,底部是字符编号:

|t|h|i|s| |i|s| |a| |t|e|s|t|
-----------------------------
|0|1|2|3|4|5|6|7|8|9|1|1|1|1|
| | | | | | | | | | |0|1|2|3|

答案 2 :(得分:0)

您可以通过以下方式使用用户输入中的char

char只是一个无符号整数值0..65535所以你可以写例如:值+的{​​{1}} [这是'+'的unicode]

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