我正在学习我的第一个Java课程,并且很难完成这项任务。
作业本身很简单。我所要做的就是提示用户输入一个整数,一个字符,然后输入另一个整数。
如果输入的字符是+,则应将两个整数相加。如果输入的字符是 - ,则应减去两个整数。等...
问题是我不知道如何接受用户的字符,然后在我的If / Switch语句中使用它。
以下是我的提示:
// Prompt the user to enter an integer
System.out.print("Please enter an integer number:");
int int1 = input.nextInt();
// Prompt the user to enter a character
// Since I could not use characters, I am using integers to represent them.
System.out.print("Enter 0 for +, 1 for -, 2 for /, 3 for %, and 4 for *");
int char1 = input.nextInt();
// Prompt the user to enter another integer
System.out.print("Please enter another integer number:");
int int2 = input.nextInt();
以下是我的If / Switch语句:(我知道它们是多余的,但它是作业的一部分)
if (char1 == 0) {
int ans = int1 + int2;
System.out.println(int1 + " + " + int2 + " = " + ans);
} else if (char1 == 1) {
int ans = int1 - int2;
System.out.println(int1 + " - " + int2 + " = " + ans);
} else if (char1 == 2) {
int ans = int1 / int2;
System.out.println(int1 + " / " + int2 + " = " + ans);
} else if (char1 == 3) {
int ans = int1 % int2;
System.out.println(int1 + " % " + int2 + " = " + ans);
} else if (char1 == 4) {
int ans = int1 * int2;
System.out.println(int1 + " * " + int2 + " = " + ans);
} else
System.out.println("Invalid operator");
int result = 0;
switch (char1) {
case 0: result = int1 + int2;
System.out.println(int1 + " + " + int2 + " = " + result); break;
case 1: result = int1 - int2;
System.out.println(int1 + " - " + int2 + " = " + result); break;
case 2: result = int1 / int2;
System.out.println(int1 + " / " + int2 + " = " + result); break;
case 3: result = int1 % int2;
System.out.println(int1 + " % " + int2 + " = " + result); break;
case 4: result = int1 * int2;
System.out.println(int1 + " * " + int2 + " = " + result); break;
default: System.out.println("Invalid operator");
}
其他一切都很好。我只是想改变使用0代表+,1代表 - ,改为使用+, - ,/,%和*。
答案 0 :(得分:2)
您可以将用户的操作符设为字符串或字符
像这样:
Scanner input = new Scanner(System.in);
// Prompt the user to enter an integer
System.out.print("Please enter an integer number:");
int int1 = input.nextInt();
// Prompt the user to enter a character
// Since I could not use characters, I am using integers to represent them.
System.out.print("Enter +, -, /, %, *");
char char1 = input.next().charAt(0);
// Prompt the user to enter another integer
System.out.print("Please enter another integer number:");
int int2 = input.nextInt();
if (char1=='+') {
int ans = int1 + int2;
System.out.println(int1 + " + " + int2 + " = " + ans);
} else if (char1=='-') {
int ans = int1 - int2;
System.out.println(int1 + " - " + int2 + " = " + ans);
} else if (char1=='/') {
int ans = int1 / int2;
System.out.println(int1 + " / " + int2 + " = " + ans);
} else if (char1=='%') {
int ans = int1 % int2;
System.out.println(int1 + " % " + int2 + " = " + ans);
} else if (char1=='*') {
int ans = int1 * int2;
System.out.println(int1 + " * " + int2 + " = " + ans);
} else {
System.out.println("Invalid operator");
}
int result = 0;
switch (char1) {
case '+':
result = int1 + int2;
System.out.println(int1 + " + " + int2 + " = " + result);
break;
case '-':
result = int1 - int2;
System.out.println(int1 + " - " + int2 + " = " + result);
break;
case '/':
result = int1 / int2;
System.out.println(int1 + " / " + int2 + " = " + result);
break;
case '%':
result = int1 % int2;
System.out.println(int1 + " % " + int2 + " = " + result);
break;
case '*':
result = int1 * int2;
System.out.println(int1 + " * " + int2 + " = " + result);
break;
default:
System.out.println("Invalid operator");
}
答案 1 :(得分:1)
你可以这样做:
System.out.print("Enter +, -, /, or *");
char char1 = input.nextLine().charAt(0);
nextLine
将获取用户输入的全部内容,charAt
获取指定索引处的字符。
因此,charAt(0)
获得第一个字符。这是一个直观的解释:顶部是字符串,底部是字符编号:
|t|h|i|s| |i|s| |a| |t|e|s|t|
-----------------------------
|0|1|2|3|4|5|6|7|8|9|1|1|1|1|
| | | | | | | | | | |0|1|2|3|
答案 2 :(得分:0)
您可以通过以下方式使用用户输入中的char
:
char
只是一个无符号整数值0..65535所以你可以写例如:值+
的{{1}} [这是'+'的unicode]
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