Question

当我发送请求时，警报为空。文件上传很好，只是没有responsetext。我在这里做错了吗？

var request = new XMLHttpRequest();

request.open('POST','upload.php');
request.setRequestHeader('Cache-Control','no-cache');
request.send(data);
alert(request.responseText);

和upload.php

if(!empty($_FILES['file'])){
foreach  ($_FILES['file']['name'] as $key => $name) {
if($_FILES['file']['error'][$key] == 0 && move_uploaded_file($_FILES['file']['tmp_name'][$key],"video/$name"))
    {
       $x = "1";
    }
        else
    {
      $x = "2";
    }
  }
}
   if ($x == "1"){echo "success";}
   if ($x == "2"){echo "failed";}

Answer 1

您已处理$x的输出，其值为1和2.如果未设置$x，该怎么办？

空的responseText发送xmlhttprequest

1 个答案: