我的选择输出如下
| s.no | user_id | user_type | user_group | prefix | fname | mname | lname | suffix |nick_name | company | department | designation_title | industry | dob | nationality | passport_number | photograph | mobile | email | permanent_address | temporary_address | bbm_p |t_number_arrival | departure_date_time | depart_airlines | flight_number_departure |
| 17 | 0 | Husband | 23 | sasas | asd | | | | | | | | |0000-00-00 | | | | 0 | asdas | | sadx | asd| 0000-00-00 00:00:00 | | |
| 18 | 0 | wife | 23 | | | | | | | | | | | 0000-00-00 | | | | 0 | | | | | 0000-00-00 00:00:00 | | |
| 19 | 0 | kid1 | 23 | | | | | | | | | | | 0000-00-00 | | | | 0 | | | | | 0000-00-00 00:00:00 | | |
| 20 | 0 | kid2 | 23 | | | | | | | | | | | 0000-00-00 | | | | 0 | | | | | 0000-00-00 00:00:00 | | |
| 21 | 0 | kid3 | 23 | | | | | | | | | | | 0000-00-00 | | | | 0 | | | | | 0000-00-00 00:00:00 | | |
| 22 | 0 | kid4 | 23 | | | | | | | | | | | 0000-00-00 | | | | 0 | | | | | 0000-00-00 00:00:00 | | |
| 23 | 0 | Husband | 24 | sasas | asd | | | | | | | | | 0000-00-00 | | | | 0 | asdas | | sadx | asd| 0000-00-00 00:00:00 | | |
| 24 | 0 | wife | 24 | | | | | | | | | | | 0000-00-00 | | | | 0 | | | | | 0000-00-00 00:00:00 | | |
| 25 | 0 | kid1 | 24 | | | | | | | | | | | 0000-00-00 | | | | 0 | | | |
我需要转换如下
| husband | wife | kid1 | kid2 | kid3 | kid4
sasas | | | | |
asd | | | | |
如何修改我的选择查询以对其下的记录进行分组 丈夫，妻子，小孩1，小孩2，小孩3和小孩4？
答案 0 :(得分：1)
您的问题并不完全清楚，但似乎您希望取消忽略现有列，然后转移 user_type列中的值。
如果是这种情况，那么您将需要使用UNION ALL取消数据的转移，然后应用带有CASE表达式的聚合函数来进行转动以获得最终结果：
select user_id,
user_group,
col_name,
max(case when user_type = 'Husband' then value end) as Husband,
max(case when user_type = 'wife' then value end) as Wife,
max(case when user_type = 'kid1' then value end) as Kid1,
max(case when user_type = 'kid2' then value end) as Kid2,
max(case when user_type = 'kid3' then value end) as Kid3,
max(case when user_type = 'ki4=d4' then value end) as Kid4
from
(
select user_id, user_type, user_group,
'prefix' as col_name, prefix as value
from yourtable
union all
select user_id, user_type, user_group,
'fname' as col_name, fname as value
from yourtable
union all
select user_id, user_type, user_group,
'mname' as col_name, mname as value
from yourtable
union all
select user_id, user_type, user_group,
'lname' as col_name, lname as value
from yourtable
union all
select user_id, user_type, user_group,
'suffix' as col_name, suffix as value
from yourtable
union all
select user_id, user_type, user_group,
'nick_name' as col_name, nick_name as value
from yourtable
union all
select user_id, user_type, user_group,
'company' as col_name, company as value
from yourtable
union all
select user_id, user_type, user_group,
'department' as col_name, department as value
from yourtable
) src
group by user_id, user_group, col_name
见SQL Fiddle with Demo。您的示例数据没有很多值，但结果与此类似：
| USER_ID | USER_GROUP | COL_NAME | HUSBAND | WIFE | KID1 | KID2 | KID3 | KID4 |
--------------------------------------------------------------------------------------------
| 0 | 23 | company | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 23 | department | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 23 | fname | asd | (null) | (null) | (null) | (null) | (null) |
| 0 | 23 | lname | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 23 | mname | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 23 | nick_name | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 23 | prefix | sasas | (null) | (null) | (null) | (null) | (null) |
| 0 | 23 | suffix | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 24 | company | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 24 | department | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 24 | fname | asd | (null) | (null) | (null) | (null) | (null) |
| 0 | 24 | lname | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 24 | mname | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 24 | nick_name | (null) | (null) | (null) | (null) | (null) | (null) |
| 0 | 24 | prefix | sasas | (null) | (null) | (null) | (null) | (null) |
| 0 | 24 | suffix | (null) | (null) | (null) | (null) | (null) | (null) |
注意：我添加了其他列以进行取消删除，但如果您只想要fname，则只需在子查询中包含这些列
编辑＃1，如果您需要根据原始表中的列保留数据的顺序，则可以使用排序顺序向UNION ALL个查询添加一列。然后，您可以在ORDER BY中使用该列。所以查询将是：
select user_id,
user_group,
col_name,
max(case when user_type = 'Husband' then value end) as Husband,
max(case when user_type = 'wife' then value end) as Wife,
max(case when user_type = 'kid1' then value end) as Kid1,
max(case when user_type = 'kid2' then value end) as Kid2,
max(case when user_type = 'kid3' then value end) as Kid3,
max(case when user_type = 'ki4=d4' then value end) as Kid4
from
(
select user_id, user_type, user_group,
'prefix' as col_name, prefix as value
, 1 as sortorder
from yourtable
union all
select user_id, user_type, user_group,
'fname' as col_name, fname as value
, 2 as sortorder
from yourtable
union all
select user_id, user_type, user_group,
'mname' as col_name, mname as value
, 3 as sortorder
from yourtable
union all
select user_id, user_type, user_group,
'lname' as col_name, lname as value
, 4 as sortorder
from yourtable
union all
select user_id, user_type, user_group,
'suffix' as col_name, suffix as value
, 5 as sortorder
from yourtable
union all
select user_id, user_type, user_group,
'nick_name' as col_name, nick_name as value
, 6 as sortorder
from yourtable
union all
select user_id, user_type, user_group,
'company' as col_name, company as value
, 7 as sortorder
from yourtable
union all
select user_id, user_type, user_group,
'department' as col_name, department as value
, 8 as sortorder
from yourtable
) src
group by user_id, user_group, col_name
order by user_group, sortorder