将二进制转换为ascii,ascii中的旋转字符串 - java

时间:2013-02-03 15:42:34

标签: java string binary rotation ascii

我是java的新手,现在我真的迷路了。我必须先将二进制文件转换为ascii。然后,创建ascii的旋转字符串(例如:“2L4R6L”)以获取特定字母。

我还在第一部分,但现在我真的输了。我尝试了转换,但是当我打印它时,null就是输出。你能帮我指出我的错误,并帮我解决这个问题吗?

以下是我创建的方法:

public void setEncryptedMessage(String encryptedMess){
    encryptedMessage = encryptedMess;
    Cipher cph = new Cipher();
    cph.convertBinary(encryptedMessage);
}

public void convertBinary(String encryptedMessage){
    StringTokenizer st = new StringTokenizer(encryptedMessage, '#');
    int convert = Integer.parseInt(st.nextToken(), 2);
    String letter = new Character((char)convert).toString();
    encryptedMessage = letter;
}   

public String getEncryptedMessage(){    
  return encryptedMessage;
}   

这是主要的:

public static void main(String[] args){ 
  Cipher cph=new Cipher();
  String encryptedMessage="1000001#1001001#1011010#1010000#1000110";    
  cph.setEncryptedMessage(encryptedMessage);    
  System.out.println(cph.getEncryptedMessage());
}

2 个答案:

答案 0 :(得分:1)

摆脱您在Cipher

中创建的额外setEncryptedMessage个对象

答案 1 :(得分:0)

所以你在将字符串中的二进制转换为ascii格式时遇到了问题,对吧?这里!我找到了解决办法!

public static void main(String[] args) {
    String encryptedMessage="1000001#1001001#1011010#1010000#1000110"; //BTW one ascii charecter is represented by 8 digits in binary. And here there are 7 digits per charecter...fix that and well moving on...
    String filtered= encryptedMessage.replaceAll("#", "");
    StringBuilder b = new StringBuilder();
    int i = 0;
    String rslt= "";
    while (i + 8 <= filtered.length()) {
    char c = convert(filtered.substring(i, i+8));
    i+=8;
    b.append(c);
    rslt= b.toString();
    }
    System.out.println(rslt);
}
private static char convert(String bs) {
    return (char)Integer.parseInt(bs, 2);
}