Question

我需要SQL Server和Oracle兼容查询才能获得以下结果

表：

PRIMARY IDN   SECONDARY_IDN    STATUS 
1             47               Pending
2             47               Completed
3             47               Error
4             57               Pending
5             59               Completed
6             60               Pending
7             60               Completed

我的输入可以是Pending，Completed或Error。

我需要列出只有1个状态的所有辅助IDN，这是输入状态。

例如我的输入是Pending：它应该只显示57。其他人可能有Pending，但也有完成和错误记录。

你能帮帮我吗？

Answer 1

SELECT  SECONDARY_IDN
FROM    tableName
GROUP   BY SECONDARY_IDN
HAVING  SUM(CASE WHEN Status = 'Pending' THEN 1 ELSE 0 END) = COUNT(*)

SQLFiddle Demo

Answer 2

您需要只有一个状态的群组。为此，您希望使用聚合：

select secondary_idn
from t
group by secondary_idn
having max(status) = min(status)  and -- all the statuses are the same
       max(status) = 'Pending'        -- and the status is Pending

Answer 3

SELECT  *
FROM  tableName tn
WHERE tn.Status = 'Pending'
AND NOT EXISTS ( SELECT *
  FROM tableName nx
  WHERE nx.SECONDARY_IDN = tn.SECONDARY_IDN
  AND nx.Status <> 'Pending'
  );

外部查询没有group by，因此所有列都可用（可怕的select *就是为了说明这一事实）
exists需要检测只有一个不需要的记录才能产生true，具有聚合（min，max，count）的解决方案可能必须扫描（并聚合）< em>整个小组以确定记录的可取性。

Answer 4

 select status
 , secondary_idn
 , count(*) records
 from theTable
 where whatever
 group by status, secondary_idn
 having count(*) = 1

用于过滤唯一状态记录的SQL查询

4 个答案: