我需要解析具有相同标记名称的XML文档。我给你一个这段代码的样本,看看我想做什么..
<SystemData>
<SystemName>xmlexample</SystemName>
<Schools>
<School>
<SchoolName>SCHOOL1</SchoolName>
<Classes>
<Class>
<ClassName>ACLASS</ClassName>
</Class>
</Classes>
<Classes>
<Class>
<ClassName>BCLASS</ClassName>
</Class>
</Classes>
</School>
<School>
<SchoolName>SCHOOL2</SchoolName>
<Classes>
<Class>
<ClassName>CCLASS</ClassName>
</Class>
</Classes>
</School>
</Schools>
</SystemData>
我想要的结果是:
SCHOOL1
ACLASS
BCLASS
SCHOOL2
CCLASS
我正在尝试使用for循环,但它让我为每个学校的所有课程。
到目前为止我的代码:
NodeList schoolist = doc.getElementsByTagName("School");
int num = schoolist.getLength();
for (int temp = 0; temp < num; temp++) {
Node nNode = schoolist.item(temp);
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) schoolist.item(temp);
Node schoolname = eElement.getFirstChild();
System.out.println("schoolname: " + eElement.getElementsByTagName("ClassName").item(0).getTextContent());
}
NodeList Classlist = doc.getElementsByTagName("Method");
int num1 = Classlist.getLength();
for (int i = 0; i < num1; i++) {
Node nNode1 = Classlist.item(i);
if (nNode1.getNodeType() == Node.ELEMENT_NODE) {
Element eElement1 = (Element) Classlist.item(i);
Node Classname = eElement1.getFirstChild();
System.out.println("Classname: " + eElement1.getElementsByTagName("ClassName").item(0).getTextContent());
}
}
}
答案 0 :(得分:1)
所以最后我设法修复了代码..这就是它的工作原理..
NodeList listOfSchool = doc.getElementsByTagName("School");
for(int s=0; s<listOfSchool.getLength() ; s++){
Node firstSchoolNode = listOfSchool.item(s);
if(firstSchoolNode .getNodeType() == Node.ELEMENT_NODE){
Element SchoolElement = (Element)firstSchoolNode ;
//-------
NodeList SchoolNameList = SchoolElement.getElementsByTagName("SchoolName");
Element SchoolNameElement = (Element)SchoolNameList .item(0);
NodeList textFNList = SchoolNameElement.getChildNodes();
System.out.println("School Name : " +
((Node)textFNList.item(0)).getNodeValue().trim());
//----
NodeList listOfSchoolNames = SchoolElement.getElementsByTagName("Class");
for(int i=0; i<listOfSchoolNames.getLength() ; i++){
Node firstClassNode = listOfSchoolNames.item(i);
if(firstClassNode .getNodeType() == Node.ELEMENT_NODE){
Element classElement = (Element)firstClassNode;
//----
NodeList ClassNameList = classElement .getElementsByTagName("ClassName");
Element ClassNameElement = (Element)ClassNameList.item(0);
NodeList textCLSNMList = ClassNameElement.getChildNodes();
System.out.println("class Name : " +
((Node)textCLSNMList .item(0)).getNodeValue().trim());
}
}
答案 1 :(得分:0)
标签名称存在一些明显问题:
System.out.println("schoolname: " + eElement.getElementsByTagName("ClassName").item(0).getTextContent());
应该是
System.out.println("schoolname: " + eElement.getElementsByTagName("SchoolName").item(0).getTextContent());
和
NodeList Classlist = doc.getElementsByTagName("Method");
应该是
NodeList Classlist = doc.getElementsByTagName("Class");
然后,您不希望从文档中获取所有Class
元素,而是获取当前学校的所有Class
个文档。
答案 2 :(得分:0)
我建议使用Java SE 5及更高版本中的javax.xml.xpath
API代替getElementsByTagName
,以使您的代码更易读,更易于维护。
import javax.xml.xpath.*;
import org.w3c.dom.*;
import org.xml.sax.InputSource;
public class Demo {
public static void main(String[] args) throws Exception {
XPathFactory xpf = XPathFactory.newInstance();
XPath xPath = xpf.newXPath();
XPathExpression schoolNameExpression = xPath.compile("SchoolName");
XPathExpression classNameExpression = xPath.compile("Classes/Class/ClassName");
InputSource inputSource = new InputSource("src/forum14671896/input.xml");
NodeList schoolNodes = (NodeList) xPath.evaluate("/SystemData/Schools/School", inputSource, XPathConstants.NODESET);
for(int x=0; x<schoolNodes.getLength(); x++) {
Node schoolElement = schoolNodes.item(x);
// School Name
System.out.print("School Name : ");
System.out.println(schoolNameExpression.evaluate(schoolElement, XPathConstants.STRING));
// Class Names
NodeList classNames = (NodeList) classNameExpression.evaluate(schoolElement, XPathConstants.NODESET);
for(int y=0; y<classNames.getLength(); y++) {
System.out.print("Class Name : ");
System.out.println(classNames.item(y).getTextContent());
}
System.out.println();
}
}
}
<强>输出强>
School Name : SCHOOL1
Class Name : ACLASS
Class Name : BCLASS
School Name : SCHOOL2
Class Name : CCLASS