我发现在where子句中使用Row_Number()函数回答了一个问题。当我尝试一个查询时，我收到以下错误：
“Ms 4108，Level 15，State 1，Line 1 窗口函数只能出现在SELECT或ORDER BY子句中。“
这是我试过的查询。如果有人知道如何解决这个问题，请告诉我。
SELECT employee_id
FROM V_EMPLOYEE
WHERE row_number() OVER ( ORDER BY employee_id ) > 0
ORDER BY Employee_ID
答案 0 :(得分：79)
要解决此问题，请将您的select语句包装在CTE中，然后您可以查询CTE并在where子句中使用窗口函数的结果。
WITH MyCte AS
(
select employee_id,
RowNum = row_number() OVER ( order by employee_id )
from V_EMPLOYEE
ORDER BY Employee_ID
)
SELECT employee_id
FROM MyCte
WHERE RowNum > 0
答案 1 :(得分：56)
SELECT employee_id
FROM (
SELECT employee_id, ROW_NUMBER() OVER (ORDER BY employee_id) AS rn
FROM V_EMPLOYEE
) q
WHERE rn > 0
ORDER BY
Employee_ID
请注意，此过滤器是多余的：ROW_NUMBER()从1开始，始终大于0。
答案 2 :(得分：25)
Select * from
(
Select ROW_NUMBER() OVER ( order by Id) as 'Row_Number', *
from tbl_Contact_Us
) as tbl
Where tbl.Row_Number = 5
答案 3 :(得分：18)
我想你想要这样的东西：
SELECT employee_id
FROM (SELECT employee_id, row_number()
OVER (order by employee_id) AS 'rownumber'
FROM V_EMPLOYEE) TableExpressionsMustHaveAnAliasForDumbReasons
WHERE rownumber > 0
答案 4 :(得分：7)
在回复有关rexem回答的评论时，关于内联视图或CTE是否会更快我会重新构建查询以使用表I，并且每个人都可以使用：sys.objects。
WITH object_rows AS (
SELECT object_id,
ROW_NUMBER() OVER ( ORDER BY object_id) RN
FROM sys.objects)
SELECT object_id
FROM object_rows
WHERE RN > 1
SELECT object_id
FROM (SELECT object_id,
ROW_NUMBER() OVER ( ORDER BY object_id) RN
FROM sys.objects) T
WHERE RN > 1
生成的查询计划完全相同。我希望在所有情况下，查询优化器都会提出相同的计划，至少在内联视图中简单替换CTE，反之亦然。
当然，请在您自己的系统上尝试自己的查询，看看是否存在差异。
此外，where子句中的row_number()是Stack Overflow上给出的答案中的常见错误。在处理select子句之前，Logicaly row_number()不可用。人们忘记了这一点，当他们回答而没有测试答案时，答案有时是错误的。 （我自己也犯了罪。）
答案 5 :(得分：4)
使用CTE（SQL Server 2005 +）：
WITH employee_rows AS (
SELECT t.employee_id,
ROW_NUMBER() OVER ( ORDER BY t.employee_id ) 'rownum'
FROM V_EMPLOYEE t)
SELECT er.employee_id
FROM employee_rows er
WHERE er.rownum > 1
使用内联视图/非CTE等效替代方法：
SELECT er.employee_id
FROM (SELECT t.employee_id,
ROW_NUMBER() OVER ( ORDER BY t.employee_id ) 'rownum'
FROM V_EMPLOYEE t) er
WHERE er.rownum > 1
答案 6 :(得分：2)
基于OP对问题的回答：
请看这个链接。它有一个 不同的解决方案，看起来 为那个问过的人工作 题。我想找出一个 像这样的解决方案。
Paginated query using sorting on different columns using ROW_NUMBER() OVER () in SQL Server 2005
〜约瑟夫
“方法1”类似于来自链接问题的OP查询，“方法2”类似于来自所选答案的查询。您必须查看此answer中链接的代码才能看到实际发生的情况，因为所选答案中的代码已被修改以使其正常工作。试试这个：
DECLARE @YourTable table (RowID int not null primary key identity, Value1 int, Value2 int, value3 int)
SET NOCOUNT ON
INSERT INTO @YourTable VALUES (1,1,1)
INSERT INTO @YourTable VALUES (1,1,2)
INSERT INTO @YourTable VALUES (1,1,3)
INSERT INTO @YourTable VALUES (1,2,1)
INSERT INTO @YourTable VALUES (1,2,2)
INSERT INTO @YourTable VALUES (1,2,3)
INSERT INTO @YourTable VALUES (1,3,1)
INSERT INTO @YourTable VALUES (1,3,2)
INSERT INTO @YourTable VALUES (1,3,3)
INSERT INTO @YourTable VALUES (2,1,1)
INSERT INTO @YourTable VALUES (2,1,2)
INSERT INTO @YourTable VALUES (2,1,3)
INSERT INTO @YourTable VALUES (2,2,1)
INSERT INTO @YourTable VALUES (2,2,2)
INSERT INTO @YourTable VALUES (2,2,3)
INSERT INTO @YourTable VALUES (2,3,1)
INSERT INTO @YourTable VALUES (2,3,2)
INSERT INTO @YourTable VALUES (2,3,3)
INSERT INTO @YourTable VALUES (3,1,1)
INSERT INTO @YourTable VALUES (3,1,2)
INSERT INTO @YourTable VALUES (3,1,3)
INSERT INTO @YourTable VALUES (3,2,1)
INSERT INTO @YourTable VALUES (3,2,2)
INSERT INTO @YourTable VALUES (3,2,3)
INSERT INTO @YourTable VALUES (3,3,1)
INSERT INTO @YourTable VALUES (3,3,2)
INSERT INTO @YourTable VALUES (3,3,3)
SET NOCOUNT OFF
DECLARE @PageNumber int
DECLARE @PageSize int
DECLARE @SortBy int
SET @PageNumber=3
SET @PageSize=5
SET @SortBy=1
--SELECT * FROM @YourTable
--Method 1
;WITH PaginatedYourTable AS (
SELECT
RowID,Value1,Value2,Value3
,CASE @SortBy
WHEN 1 THEN ROW_NUMBER() OVER (ORDER BY Value1 ASC)
WHEN 2 THEN ROW_NUMBER() OVER (ORDER BY Value2 ASC)
WHEN 3 THEN ROW_NUMBER() OVER (ORDER BY Value3 ASC)
WHEN -1 THEN ROW_NUMBER() OVER (ORDER BY Value1 DESC)
WHEN -2 THEN ROW_NUMBER() OVER (ORDER BY Value2 DESC)
WHEN -3 THEN ROW_NUMBER() OVER (ORDER BY Value3 DESC)
END AS RowNumber
FROM @YourTable
--WHERE
)
SELECT
RowID,Value1,Value2,Value3,RowNumber
,@PageNumber AS PageNumber, @PageSize AS PageSize, @SortBy AS SortBy
FROM PaginatedYourTable
WHERE RowNumber>=(@PageNumber-1)*@PageSize AND RowNumber<=(@PageNumber*@PageSize)-1
ORDER BY RowNumber
--------------------------------------------
--Method 2
;WITH PaginatedYourTable AS (
SELECT
RowID,Value1,Value2,Value3
,ROW_NUMBER() OVER
(
ORDER BY
CASE @SortBy
WHEN 1 THEN Value1
WHEN 2 THEN Value2
WHEN 3 THEN Value3
END ASC
,CASE @SortBy
WHEN -1 THEN Value1
WHEN -2 THEN Value2
WHEN -3 THEN Value3
END DESC
) RowNumber
FROM @YourTable
--WHERE more conditions here
)
SELECT
RowID,Value1,Value2,Value3,RowNumber
,@PageNumber AS PageNumber, @PageSize AS PageSize, @SortBy AS SortBy
FROM PaginatedYourTable
WHERE
RowNumber>=(@PageNumber-1)*@PageSize AND RowNumber<=(@PageNumber*@PageSize)-1
--AND more conditions here
ORDER BY
CASE @SortBy
WHEN 1 THEN Value1
WHEN 2 THEN Value2
WHEN 3 THEN Value3
END ASC
,CASE @SortBy
WHEN -1 THEN Value1
WHEN -2 THEN Value2
WHEN -3 THEN Value3
END DESC
输出：
RowID Value1 Value2 Value3 RowNumber PageNumber PageSize SortBy
------ ------ ------ ------ ---------- ----------- ----------- -----------
10 2 1 1 10 3 5 1
11 2 1 2 11 3 5 1
12 2 1 3 12 3 5 1
13 2 2 1 13 3 5 1
14 2 2 2 14 3 5 1
(5 row(s) affected
RowID Value1 Value2 Value3 RowNumber PageNumber PageSize SortBy
------ ------ ------ ------ ---------- ----------- ----------- -----------
10 2 1 1 10 3 5 1
11 2 1 2 11 3 5 1
12 2 1 3 12 3 5 1
13 2 2 1 13 3 5 1
14 2 2 2 14 3 5 1
(5 row(s) affected)
答案 7 :(得分：2)
WITH MyCte AS
(
select
employee_id,
RowNum = row_number() OVER (order by employee_id)
from V_EMPLOYEE
)
SELECT employee_id
FROM MyCte
WHERE RowNum > 0
ORDER BY employee_id
答案 8 :(得分：1)
我觉得所有使用CTE或子查询的答案都足以解决此问题，但是我看不出有人对OP有问题的原因深感兴趣。 OP提出的建议不起作用的原因是由于此处的逻辑查询处理顺序：
- 从
- 开启
- 加入
- 在哪里
- 组别
- 多维数据集/卷
- 拥有
- 选择
- DISTINCT
- ORDER BY
- TOP
- 偏移量/ FETCH
我相信这对答案很有帮助，因为它解释了为什么会发生此类问题。 WHERE总是在SELECT之前进行处理，使得许多功能都需要CTE或子查询。您会在SQL Server中看到很多。
答案 9 :(得分：-1)
select salary from (
select Salary, ROW_NUMBER() over (order by Salary desc) rn from Employee
) t where t.rn = 2