Question

我有三张桌子。 SurveyFact，问题和回应。调查事实包含客户调查的数据，而问题和答复表有明显的数据，问题列表和每个问题的可能答案。

SurveyFact：

| SurveyFactID | ClientID   |  QuestionID   | ResponseCode |
------------------------------------------------------------
|    1         |    1       |     1         |     3        |    
|    2         |    1       |     2         |     3        |
|    3         |    1       |     3         |     1        |

问题：

| QuestionID| QuestionText          |
-------------------------------------
|    1      |    blah blah blah     |    
|    2      |    blah blah blah     |
|    3      |    blah blah blah     |

响应：

| ResponseID| QuestionID  | ResponseCode |ResponseText     |
-----------------------------------------------------------|
|    1      |    1       |      1       |   like           |    
|    2      |    1       |      2       |   don't care     |
|    3      |    1       |      3       |   hate           |
|    4      |    2       |      1       |   like           |    
|    5      |    2       |      2       |   don't care     |
|    6      |    2       |      3       |   hate           |

这是我提出的查询。（那失败了）

select
    sf.QuestionCode as [Question Number],
    q.QuestionText as [Question Text],
    r.ResponseText as [Reponse]
from SurveyFact sf
inner join Question q
    on q.QuestionID = sf.QuestionID
inner join Responses r
    on r.ResponseCode = sf.ResponseCode
where sf.ClientID = '1'
    and sf.QuestionID = q.QuestionID
    and sf.ResponseCode = r.ResponseCode

即使我使用select distinct，它也会向我提供每个可能答案的调查和问题，而不仅仅是SurveyFact中列出的问题/答案组合。

请帮忙吗？

请求表：我在看什么

| Question Number | Question Text |Response Text     |
------------------------------------------------------
|    1       |  blah blah blah    |   like           |    
|    1       |  blah blah blah    |   don't care     |
|    1       |  blah blah blah    |  hate            |
|    2       |  blah blah blah    |   like           |    
|    2       |  blah blah blah    |   don't care     |
|    2       |  blah blah blah    |   hate           |

我想要的是什么：

| Question Number | Question Text |Response Text     |
------------------------------------------------------ 
|    1       |  blah blah blah    |   don't care     |
|    2       |  blah blah blah    |   like           |

首先是Number，QUestion，然后是每个可能的答案。第二个是数字，问题，刚选择的答案

Answer 1

select
    sf.QuestionID as QuestionNumber,
    q.QuestionText as QuestionText,
    r.ResponseText as Reponse
from SurveyFact sf, Question  q, Response  r
where sf.ClientID = '1'
and
sf.QuestionID = q.QuestionID
and
r.QuestionID = q.QuestionID
and
sf.ResponseCode = r.ResponseCode

我认为你正在寻找。

结果将是：

| Question Number | Question Text |Response Text     |
------------------------------------------------------ 
|    1       |  blah blah (q1)    |   hate           |
|    2       |  blah blah (q2)    |   hate           |

在你的结果中写道：

| Question Number | Question Text |Response Text     |
------------------------------------------------------ 
|    1       |  blah blah blah    |   don't care     |
|    2       |  blah blah blah    |   like           |

但我看不出应该如何“不关心”和“喜欢”？他们有ResponseCode 1和2。并且ResultCode 1和2不在SurveyFact中。井1是，但它适用于问题3，问题3不在响应表中。

Answer 2

添加一个条件，响应必须是正确的问题：

inner join Responses r
    on r.ResponseCode = sf.ResponseCode
       and r.QuestionID = q.QuestionID

在形成SQL查询时遇到问题

2 个答案: