Question

我收到了以下代码：

int nnames;
String names[];

System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = in.nextInt();
names = new String[nnames];

for (int i = 0; i < names.length; i++){
  System.out.print("Type a name: ");
  names[i] = in.nextLine();
}

该代码的输出如下：

How many names are you going to save:3 
Type a name: Type a name: John Doe
Type a name: John Lennon

注意它是如何跳过第一个名字的？它跳过它并直接进入第二个名称输入。我试过看是什么导致了这个，但我似乎无法指出它。我希望有一个人可以帮助我。感谢

Answer 1

错误的原因是nextInt只拉取整数，而不是换行符。如果你在for循环之前添加一个in.nextLine（），它将占用空的新行并允许你输入3个名字。

int nnames;
String names[];

System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = in.nextInt();

names = new String[nnames];
in.nextLine();
for (int i = 0; i < names.length; i++){
        System.out.print("Type a name: ");
        names[i] = in.nextLine();
}

或者只是读取该行并将该值解析为整数。

int nnames;
String names[];

System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = Integer.parseInt(in.nextLine().trim());

names = new String[nnames];
for (int i = 0; i < names.length; i++){
        System.out.print("Type a name: ");
        names[i] = in.nextLine();
}

Answer 2

使用sc.nextLine（）;两次，以便我们可以读取字符串的最后一行

sc.nextLine（） sc.nextLine（）

Answer 3

这是因为in.nextInt（）不会改变行。因此，首先“输入”（按3后）会导致循环中的in.nextLine（）读取endOfLine。

您可以执行以下小改动：

int nnames;
    String names[];

    System.out.print("How many names are you going to save: ");
    Scanner in = new Scanner(System.in);
    nnames = Integer.parseInt(in.nextLine());
    names = new String[nnames];

    for (int i = 0; i < names.length; i++){
            System.out.print("Type a name: ");
            names[i] = in.nextLine();
    }

Answer 4

这是因为in.nextInt（）只接收一个int号，不接收新行。因此，您输入3并按“Enter”，行尾由in.nextline（）读取。

这是我的代码：

int nnames;
String names[];

System.out.print("How many names are you going to save: ");
Scanner in = new Scanner(System.in);
nnames = in.nextInt();
in.nextLine();
names = new String[nnames];

for (int i = 0; i < names.length; i++){
        System.out.print("Type a name: ");
        names[i] = in.nextLine();
}

Java Scanner类读取字符串

4 个答案: