我有一个UIPicker,我想改变选择器的颜色。是否可以更改选择器的颜色?
答案 0 :(得分:21)
也许它不完全适合回答这个问题,在iOS 7及更高版本中你可以通过这种方式自定义颜色:
在委托方法
中- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view
- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
添加以下
[[pickerView.subviews objectAtIndex:1] setBackgroundColor:NEEDED_COLOR];
[[pickerView.subviews objectAtIndex:2] setBackgroundColor:NEEDED_COLOR];
<强>更新强>
以前的代码有效,但马马虎虎。这里是UIPickerView的简单子类
夫特:
class RDPickerView: UIPickerView
{
@IBInspectable var selectorColor: UIColor? = nil
override func didAddSubview(subview: UIView) {
super.didAddSubview(subview)
if let color = selectorColor
{
if subview.bounds.height <= 1.0
{
subview.backgroundColor = color
}
}
}
}
目标-C:
@interface RDPickerView : UIPickerView
@property (strong, nonatomic) IBInspectable UIColor *selectorColor;
@end
@implementation RDPickerView
- (void)didAddSubview:(UIView *)subview
{
[subview didAddSubview:subview];
if (self.selectorColor)
{
if (subview.bounds.size.height <= 1.0)
{
subview.backgroundColor = self.selectorColor;
}
}
}
@end
您可以直接在故事板中设置选择器颜色
感谢Ross Barbish - “2015年12月8日发布了iOS 9.2和XCode 7.2,此选择视图的高度为0.666666666666667”。
更新:
它解决了iOS 10的问题,不好但有效。 :/
class RDPickerView: UIPickerView
{
@IBInspectable var selectorColor: UIColor? = nil
override func didAddSubview(_ subview: UIView) {
super.didAddSubview(subview)
guard let color = selectorColor else {
return
}
if subview.bounds.height <= 1.0
{
subview.backgroundColor = color
}
}
override func didMoveToWindow() {
super.didMoveToWindow()
guard let color = selectorColor else {
return
}
for subview in subviews {
if subview.bounds.height <= 1.0
{
subview.backgroundColor = color
}
}
}
}
感谢Dmitry Klochkov,我会尝试找到更好的解决方案。
答案 1 :(得分:11)
这是对vsilux答案的改进,以UIPickerView的简单类别的形式,而不需要子类化UIPickerView。
(截至2018年11月2日的最新答案)
Swift 4,Xcode 10:
@IBInspectable var selectorColor: UIColor? {
get {
return objc_getAssociatedObject(self, &selectorColorAssociationKey) as? UIColor
}
set(newValue) {
objc_setAssociatedObject(self, &selectorColorAssociationKey, newValue,
objc_AssociationPolicy.OBJC_ASSOCIATION_RETAIN)
}
}
open override func didAddSubview(_ subview: UIView) {
super.didAddSubview(subview)
if let color = selectorColor {
if subview.bounds.height < 1.0 {
subview.backgroundColor = color
}
}
}
答案 2 :(得分:4)
我想你正在处理iPhone SDK?可能有一些其他框架使用此名称,因此您可以添加标签以包含uikit,cocoa-touch等。
无论如何,您可以将UIPickerView实例的showsSelectionIndicator
设置为NO,因此它会隐藏选择器。然后,您可以使用调整后的选择样式创建一个新视图,并将其添加到UIPickerView上方的超级视图中。
// Some sample code, but you can do this in IB if you want to
_pickerView = [[UIPickerView alloc] init];
_pickerView.showsSelectionIndicator = NO;
[_pickerView sizeToFit];
[self.view addSubview:_pickerView];
UIImage *selectorImage = [UIImage imageNamed:@"selectorImage.png"]; // You have to make it strechable, probably
UIView *customSelector = [[UIImageView alloc] initWithImage:selectorImage];
customSelector.frame = CGRectZero; // Whatever rect to match the UIImagePicker
[self.view addSubview:customSelector];
[customSelector release];
攻击UI元素本身将需要更多的工作,而且这也必须起作用。
答案 3 :(得分:0)
您也可以只更改选择指标的背景颜色 只需在选择指示器上方添加一个UIView (它将成为您的叠加视图),将其设置为 alpha值低(取决于您,但我喜欢我的叠加层看起来透明) ,给它一个背景色,你很高兴。
考虑一下,
var overlayOnPicker:UIView = UIView(frame: CGRectMake(1, 68, mypicker.frame.width, 26))
// Adds a layer on the selection indicator
确实把 CGRect的X值= 1 (请记住,它是一个框架,因此它将根据superview的坐标系放置)
overlayOnPicker.backgroundColor = UIColor.whiteColor()
overlayOnPicker.alpha = 0.2
myDatePicker.addSubview(overlayOnPicker)
// You have to add the overlayOnPicker view as a subview to the Date Picker.
// myDatePicker is the UIDatePicker that I declared earlier in my code
答案 4 :(得分:0)
您还可以继承UIPickerView的子类并添加以下自定义项:
"runtime": {
"type": "date",
"format": "HH_mm_ss_SS"
},