在项目上工作.. Ac-photography.net
需要帮助联系表格。它似乎没有发送,我不断得到“意外的错误消息”
<div class="contact_form">
<div class="done">
<b>Thank you!</b> I have received your message.
</div>
<form method="post" action="process.php">
<p>name</p>
<input type="text" name="name" class="text" />
<p>email</p>
<input type="text" name="email" class="text" id="email" />
<p>message</p>
<textarea name="comment" class="text textarea"></textarea>
<input type="submit" id="submit" value="send" class="submit-button" />
</form>
不知道如何在这里放置PHP。
感谢任何帮助。谢谢。
<?php
//Retrieve form data.
//GET - user submitted data using AJAX
//POST - in case user does not support javascript, we'll use POST instead
$name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
$comment = ($_GET['comment']) ?$_GET['comment'] : $_POST['comment'];
//flag to indicate which method it uses. If POST set it to 1
if ($_POST) $post=1;
//Simple server side validation for POST data, of course, you should validate the email
if (!$name) $errors[count($errors)] = 'Please enter your name.';
if (!$email) $errors[count($errors)] = 'Please enter your email.';
if (!$comment) $errors[count($errors)] = 'Please enter your comment.';
//if the errors array is empty, send the mail
if (!$errors) {
//recipient
$to = 'Your Name <alex.cherkasov@gmail.com>'; // <--------- change your email here
//sender
$from = $name . ' <' . $email . '>';
//subject and the html message
$subject = 'Message from ' . $name;
$message = '
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head></head>
<body>
<table>
<tr><td>Name</td><td>' . $name . '</td></tr>
<tr><td>Email</td><td>' . $email . '</td></tr>
<tr><td>Message</td><td>' . nl2br($comment) . '</td></tr>
</table>
</body>
</html>';
//send the mail
$result = sendmail($to, $subject, $message, $from);
//if POST was used, display the message straight away
if ($_POST) {
if ($result) echo 'Thank you! We have received your message.';
else echo 'Sorry, unexpected error. Please try again later';
//else if GET was used, return the boolean value so that
//ajax script can react accordingly
//1 means success, 0 means failed
} else {
echo $result;
}
//if the errors array has values
} else {
//display the errors message
for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>';
echo '<a href="form.php">Back</a>';
exit;
}
//Simple mail function with HTML header
function sendmail($to, $subject, $message, $from) {
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$headers .= 'From: ' . $from . "\r\n";
$result = mail($to,$subject,$message,$headers);
if ($result) return 1;
else return 0;
}
?>
答案 0 :(得分:0)
表单未正确处理,因为它没有获得任何值。请查看 contact-form.js 。
您正在构建data
变量:
var data = 'name=' + name.val() + '&email=' + email.val() + '&website=' + website.val() + '&comment=' + encodeURIComponent(comment.val());
但是在AJAX调用中,您传递的值为data
的字符串:
//pass the data
data: "data",
请改为尝试:
//pass the data
data: data,
当我简单地调用这样的脚本时:
http://ac-photography.net/process.php?email=test@test.com&name=name&comment=comment
我会收到警告:
警告:mail()[function.mail]:SMTP服务器响应:550&gt;第72行的D:\ Hosting \ 6405740 \ html \ process.php中的地址无效
修复此问题并检查邮件是否正确发送。它将按预期返回1
。