junit和hibernate - 正确的设置和拆卸以及两者之间的测试

时间:2013-02-01 20:13:09

标签: hibernate junit4

我正在尝试为持久性课程正确设置junit测试,即使我得到'绿色条',我也担心几件事情。 当我在调试器中运行测试文件时,我可以看到testList()所有对象都按预期加载,如果有任何一个有子项,它们也会被加载。

For testList(), after I do...
instance.update(sg);
List <SettingsGroup> sl = instance.list();

...我在调试器(最后的截图)中看到没有加载子项。

更新元素并将其检索回以验证更新确实发生的正确方法是什么? 现在我正在做类似

的事情
instance.update(sg);
List <SettingsGroup> sl = instance.list();

......但我不确定。

当我尝试testDelete()时,elments列表的大小与删除前的大小相同,这让我感到奇怪。

当试图研究hibernate测试时,我遇到了很多简单的例子,但我还没有得到如何正确设置,拆除和任何会话/事务管理。

我对应这个类的表有5个'硬编码'行,所以我很确定'读'调用。

TEST CLASS

@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration( locations = {"applicationContext.xml"})
@Transactional
public class SettingGroupDaoTest extends AbstractJUnit4SpringContextTests {

    public SettingGroupDaoTest(){}
    SettingGroupDao instance;

    @BeforeClass
    public static void setUpClass() throws Exception {}

    @AfterClass
    public static void tearDownClass() throws Exception {}

    @Before
    public void setUp()   {
        Configuration c  = HibernateConfiguration.getHibernateConfiguration()
                .configuration(SettingsGroup.class);

        SessionFactory sessionFactory = c.buildSessionFactory();
        instance = new SettingGroupDao();
        instance.setSessionFactory( sessionFactory );
    }

    @Test
    public void testList() throws Exception {
        SettingsGroup sq = instance.get(1);
        SettingsGroup s1 = sq.getChildren().get(0);
        System.out.println( "children index 2 name: " + s1.getName() );
        System.out.println( "2nd element of children: " + sq.getChildren().get(1).getName() );
    }

    @Test
    public void testUpdate() throws Exception{
        SettingsGroup sg = instance.get(1);
        sg.setName("Updated Name of Setting Group");
        instance.update(sg);
        List <SettingsGroup> sl = instance.list();
        Hibernate.initialize( instance.list() );
        System.out.println( "UPDATED Settings Group Name: " + sg.getName() );
    }

    @Test
    public void testDelete() throws Exception{
        instance.delete( 0 );
        int s = instance.list().size();
        System.out.println( "Size after delete: " + s );
    }
}

上面的测试配置:

public class HibernateConfiguration {
    private HibernateConfiguration(){}
    public Configuration configuration( java.lang.Class clazz ) {
        Configuration c = new Configuration();
        c.setProperty(Environment.DRIVER, "org.postgresql.Driver");
        c.setProperty(Environment.URL, "jdbc:postgresql://localhost/###");
        c.setProperty(Environment.USER, "postgres");
        c.setProperty(Environment.PASS, "####");
        c.setProperty(Environment.DIALECT, "org.hibernate.dialect.PostgreSQLDialect");
        c.setProperty(Environment.AUTOCOMMIT, "true"); //"true");
        c.addClass( clazz );
        return c;
    }
    public static HibernateConfiguration getHibernateConfiguration(){
        return new HibernateConfiguration();
    }
}

DOMAIN CLASS:

@Entity
@SequenceGenerator(name = "settings_group_id_seq", sequenceName = "settings_group_id_seq")
@Cache(usage= CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@Table(name="settings_group")
public class SettingsGroup implements Serializable, DomainObject {

    private int id;
    private String name;
    private String code;

    private List<SettingsGroup> children = new LinkedList<SettingsGroup>();

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO, generator = "settings_group_id_seq")
    @Column(name = "id", insertable = false)
    public int getId() {return id;}

    public void setId(int id) {this.id = id;}

    @Column(name = "name")
    public String getName() {return name;}

    public void setName(String name) {this.name = name;}

    @Column( name = "code")
    public String getCode() {return code; }

    public void setCode(String code) {this.code = code;}


    @OneToMany( fetch = FetchType.EAGER)
    @JoinColumn( name = "parent_id")
    @OrderColumn
    public List<SettingsGroup> getChildren() {return children;}

    public void setChildren(List<SettingsGroup> children) {this.children = children;}
}

enter image description here

1 个答案:

答案 0 :(得分:0)

一些想法......你所做的实际上是一个集成测试,因为它需要一个数据库。其次,不是肯定的,但是在成功查询更新的行之前,是否必须提交更新?