我正在尝试在ajax调用成功完成后发送电子邮件。我无法访问我正在进行AJAX调用的文件。
我阻止第一次提交,进行ajax调用并在竞争时再次提交表单。这样做时,我似乎无法弄清楚为什么我必须按两次提交按钮才能发送电子邮件。
这是我的代码:
"use strict";
var submitted = '';
/* Send info to the portal */
jQuery(function($) {
$('#quote').submit(function(e){
var firstName = $('#firstName').val(),
lastName = $('#lastName').val(),
email = $('#email').val(),
phone = $('#primaryPhone').val(),
weight = $('#weight').val(),
origin = $('#originPostalCode').val(),
destination = $('#destinationPostalCode').val(),
notes = $('#whatsTransported').val()
if( submitted != 1 )
{
e.preventDefault();
$.ajax({
type: "POST",
url: "https://somewhere.on/the/internet.php",
crossDomain: true,
dataType: "json",
data: {"key": "my secret key","first": firstName, "last": lastName, "email": email, "phone": phone, "weight": weight, "origin_postal": origin, "dest_country": destination, "note": notes }
})
.done(function(data){
if(data[1][0][0] == 2)
{
$('.alert').append( data[1][0][1].message ).addClass('alert-error').show();
} else if(data[1][0][0] == 0) {
console.log("Made it.");
$('#quote #submit').submit();
} else {
$('.alert').append( "Appologies, it seems like something went wrong. Please, <strong>call (877) 419-5523</strong> for immediate assistance or a free quote.");
}
})
.fail(function(data) { console.log(data); });
}
submitted = '1';
});
});
以下是表单HTML
<form action="<?php echo bloginfo($show='template_url').'/includes/form-email.php'; ?>" class="span6 offset1" id="quote" method="post">
<div class="row formRow">
<div class="firstName span3">
<label for="firstName"><?php _e('First Name:','StreamlinedService'); ?></label>
<input type="text" name="firstName" id="firstName">
</div>
<div class="lastName span3">
<label for="lastName"><?php _e('Last Name:','StreamlinedService'); ?></label>
<input type="text" name="lastName" id="lastName">
</div>
</div>
<div class="row formRow">
<div class="email span3">
<label for="email"><?php _e('Email Address:','StreamlinedService'); ?></label>
<input type="text" name="email" id="email">
</div>
<div class="primaryPhone span3">
<label for="primaryPhone"><?php _e('Phone Number:','StreamlinedService'); ?></label>
<input type="text" name="primaryPhone" id="primaryPhone">
</div>
</div>
<div class="row formRow">
<div class="weight span2">
<label for="weight"><?php _e('Weight (lbs):','StreamlinedService'); ?></label>
<input type="text" name="weight" id="weight">
</div>
</div>
<div class="row formRow">
<div class="originPostalCode span3">
<label for="originPostalCode"><?php _e('Origin:','StreamlinedService'); ?></label>
<input type="text" name="originPostalCode" id="originPostalCode">
</div>
<div class="destinationPostalCode span3">
<label for="destinationPostalCode"><?php _e('Destination:','StreamlinedService'); ?></label>
<input type="text" name="destinationPostalCode" id="destinationPostalCode">
</div>
</div>
<div class="row">
<div class="whatsTransported span6">
<label for="whatsTransported"><?php _e('What can we help you transport?','StreamlinedService'); ?></label>
<textarea name="whatsTransported" id="whatsTransported" rows="5"></textarea>
</div>
<input type="hidden" name="formType" value="quote" />
<input type="hidden" name="siteReferer" value="<?php echo $blog_id ?>">
<input type="submit" id="submit" name="submit" value="<?php _e('Get Freight Quote','StreamlinedService') ?>" class="btn btn-primary btn-large span3 offset3" style="float:right;">
</div>
</form>
我的问题有两方面:有没有更有效的方法来做到这一点?如果没有,为什么这不起作用?
答案 0 :(得分:0)
你对Jquery使用了错误的方法 你错过了关键:写得更少,这是JQuery的核心。 无论如何试试这个:
"use strict";
/* Send info to the portal */
jQuery(function($) {
$('#quote').submit(function(e){
var tis = $(this);
$.ajax({
type: "POST",
url: "https://somewhere.on/the/internet.php",
cache: true,
dataType: "json",
data: tis.serialize(),
success: function(data){
if(data[1][0][0] == 2){
$('.alert').append( data[1][0][1].message ).addClass('alert-error').show();
} else if(data[1][0][0] == 0) {
console.log("Made it.");
$('#quote #submit').submit();
} else {
$('.alert').append( "Appologies, it seems like something went wrong. Please, <strong>call (877) 419-5523</strong> for immediate assistance or a free quote.");
}
},
error: function(data){console.log(data);}
});
e.stroPropagation();
e.preventDefault();
});
});
上次瘦...你不能请求一个远程页面没有托管在脚本的同一个域上..对于那个This answer
答案 1 :(得分:0)
直接在表单节点上使用.submit
(请注意[0]
)
$('#quote #submit').submit();
变为
$('#quote')[0].submit();
这会绕过jQuery绑定事件并强制回发。