Question

我想缩短这段代码，我知道我可能不知道正确的语法

我想创建一个子程序来更新字体颜色，只需更改第一个单元格字母就可以从if语句调用它

有人会介意帮助，所以我可以记住这一点以供将来参考

提前感谢，

编辑：只是为了澄清，我想做这样的事情

    If Not Intersect(Target, Range("C3")) Is Nothing Then 'do the following if e3 is updated

'reset all font colors to black
Range("C8:K9,C14:K14,C37:K37").Font.ColorIndex = 1
Range("C7:K7,C11:K11,C13:K13,C23:K23,C28:K28").Font.ColorIndex = 1
Range("C10:K10,C15:K16").Font.ColorIndex = 1
Range("C17:K17").Font.ColorIndex = 1
Range("C18:K18,C33:K33").Font.ColorIndex = 1
Range("C24:K26,C29:K31").Font.ColorIndex = 1
Range("C32:K32").Font.ColorIndex = 1
Range("C36:K36,C38:K38").Font.ColorIndex = 1

    If Range("C3") = "1" Then ' do the following if C3 is 1
         updateFontColor c
    ElseIf Range("C3") = "2" Then ' do the following if C3 is 2
        updateFontColor d
    ElseIf Range("C3") = "3" Then ' do the following if C3 is 3
          updateFontColor e 
    ElseIf Range("C3") = "4" Then ' do the following if C3 is 4
        updateFontColor f

    ElseIf Range("C3") = "5" Then ' do the following if C3 is 5
        updateFontColor g

    ElseIf Range("C3") = "6" Then ' do the following if C3 is 6
              updateFontColor h     
    ElseIf Range("C3") = "7" Then ' do the following if C3 is 7
            updateFontColor i       
    ElseIf Range("C3") = "8" Then ' do the following if C3 is 8
            updateFontColor j       
    ElseIf Range("C3") = "9" Then ' do the following if C3 is 9
           updateFontColor k
               End If
End If

Sub updateFontColor(x As Range)
        Range("x8:K9,x14:x14,x37:K37").Font.ColorIndex = 2
        Range("x7:K7,x11:K11,x13:K13,x23:K23,x28:K28").Font.ColorIndex = 39
        Range("x10:K10,x15:K16").Font.ColorIndex = 35
        Range("x17:K17").Font.ColorIndex = 28
        Range("x18:K18,x33:K33").Font.ColorIndex = 38
        Range("x24:K26,x29:K31").Font.ColorIndex = 36
        Range("x32:K32").Font.ColorIndex = 44
        Range("x36:K36,x38:K38").Font.ColorIndex = 15
End Sub

Answer 1

字符串连接运算符：＆amp;

将变量x作为字符串传递：

通过传递字符串来调用您的sub：

updateFontColor("K")

子：

Sub updateFontColor(x As String) 'pass x as string, not range
    Range(x & "8:K9," & x & "14:K14," & x & "37:K37").Font.ColorIndex = 2
    .
    .
    .
End Sub

EXCEL vba子程序用于范围更新的通过字母

1 个答案: