我有以下数据框：
foo <- data.frame( abs( cbind(rnorm(3),rnorm(3, mean=.8),rnorm(3, mean=.9),rnorm(3, mean=1))))
colnames(foo) <- c("w","x","y","z")
rownames(foo) <- c("n","q","r")
foo
# w x y z
# n 1.51550092 1.4337572 1.2791624 1.1771230
# q 0.09977303 0.8173761 1.6123402 0.1510737
# r 1.17083866 1.2469347 0.8712135 0.8488029
我想要做的是将其改为：
newdf
# 1 n w 1.51550092
# 2 q w 0.09977303
# 3 r w 1.17083866
# 4 n x 1.43375725
# 5 q x 0.81737606
# 6 r x 1.24693468
# 7 n y 1.27916241
# 8 q y 1.61234016
# 9 r y 0.87121353
# 10 n z 1.17712302
# 11 q z 0.15107369
# 12 r z 0.84880292
这样做的方法是什么？
答案 0 :(得分：8)
有几种方法可以做到这一点。这是一个：
set.seed(1)
foo <- data.frame( abs( cbind(rnorm(3),
rnorm(3, mean=.8),
rnorm(3, mean=.9),
rnorm(3, mean=1))))
colnames(foo) <- c("w","x","y","z")
rownames(foo) <- c("n","q","r")
foo
# w x y z
# n 0.6264538 2.39528080 1.387429 0.6946116
# q 0.1836433 1.12950777 1.638325 2.5117812
# r 0.8356286 0.02046838 1.475781 1.3898432
data.frame(rows = row.names(foo), stack(foo))
# rows values ind
# 1 n 0.62645381 w
# 2 q 0.18364332 w
# 3 r 0.83562861 w
# 4 n 2.39528080 x
# 5 q 1.12950777 x
# 6 r 0.02046838 x
# 7 n 1.38742905 y
# 8 q 1.63832471 y
# 9 r 1.47578135 y
# 10 n 0.69461161 z
# 11 q 2.51178117 z
# 12 r 1.38984324 z
答案 1 :(得分：6)
reshape2:::melt()特别适合这种转变：
library(reshape2)
foo <- cbind(ID=rownames(foo), foo)
melt(foo)
# Using ID as id variables
# ID variable value
# 1 n w 1.7337416
# 2 q w 0.5890877
# 3 r w 0.2245508
# 4 n x 0.5237346
# 5 q x 0.9320455
# 6 r x 0.8156573
# 7 n y 1.9287306
# 8 q y 1.1604229
# 9 r y 1.7631215
# 10 n z 0.3591350
# 11 q z 0.9740170
# 12 r z 0.5621968