Question

如何编写查询以查找以下数据空白。

- Scenario1 - Query1 - 找到同一表内的差距（例如tableb）

ID      EFF_DT                                  TERM_DT 
800    6/15/2012 12:00:00.000 AM    10/14/2012 12:00:00.000 AM      -- GAP 
800    10/16/2012 12:00:00.000 AM    11/14/2012 12:00:00.000 AM
800    11/15/2012 12:00:00.000 AM    12/31/9999 12:00:00.000 AM

- Scenario2 - Query2 - 找出2个表（tablea，tableb）之间的不匹配

-- tablea  , sample data below 
ID      EFF_DT                                  TERM_DT 
400    6/15/2012 12:00:00.000 AM    10/14/2012 12:00:00.000 AM      
400    11/15/2012 12:00:00.000 AM    12/31/9999 12:00:00.000 AM

500    6/15/2012 12:00:00.000 AM    10/14/2012 12:00:00.000 AM      
500    10/15/2012 12:00:00.000 AM    11/14/2012 12:00:00.000 AM      
500    11/15/2012 12:00:00.000 AM    12/31/9999 12:00:00.000 AM

-- tableb, sample data below 
ID      EFF_DT                                  TERM_DT 
400    6/15/2012 12:00:00.000 AM    10/13/2012 12:00:00.000 AM      -- mismatch 
400    11/15/2012 12:00:00.000 AM    12/31/9999 12:00:00.000 AM

500    6/15/2012 12:00:00.000 AM    11/14/2012 12:00:00.000 AM      
500    11/15/2012 12:00:00.000 AM    12/31/9999 12:00:00.000 AM


-- Note 400 is a mismatch since ranges are different in both tables, 500 is okay (even though rows are split they still match )
-- Need to identify ID 400

对于低日期，表格有时为1/1/1753而对于高日期有时为12/31/9999。

尝试了以下查询，但它会在第一个方案中抛出oracle错误。 [ORA-01841 :(完整）年份必须介于-4713和+9999之间，而不是0]

SELECT ID, TERM_DT AS gap_lower_bound, next_date AS gap_upper_bound
  FROM (SELECT t.*,
               LEAD (EFF_DT)
                  OVER (PARTITION BY ID ORDER BY EFF_DT)
                  next_date
          FROM TABLEB t)
 WHERE                                      -- trim(next_date) is not null and
      next_date > TERM_DT + 1

谢谢。

Answer 1

for Scenario1 ,, 让我们来看一个样本，

    ID    EFF_DT         TERM_DT 
____________________________________
    800 15-JUN-12   14-OCT-12 --GAP
    800 16-OCT-12   14-NOV-12
    800 15-NOV-12   31-DEC-12
    800 01-JAN-13   01-FEB-13  --GAP
    800 03-FEB-13   01-MAR-13

查询可以是

    SELECT term_dt
FROM
     (SELECT t.*,
          lead(eff_dt,1) OVER (ORDER BY eff_dt) AS next_date
     FROM lead_test t
     )
WHERE term_dt+1<>next_date;

结果：

 term_dt
__________
14-OCT-12
01-FEB-13

for scenario2：

由于select to_date('12/31/9999', 'mm/dd/yyyy')+1 from dual;会抛出相同的错误。

由于您在ORA-01841中使用的where子句中的条件，导致TERM_DT + 1错误，因此您应该更改/减少12/31/9999中的值。

Oracle查询在日期中查找差距，比较差距的日期范围

1 个答案: