我在GridView FirstName
和LastName
中有两列。我希望FirstName列中的所有行都在超链接中。我试过这个但是没用。我该怎么办?
分析器错误
Parser Error Message: Databinding expressions are only supported on objects
that have a DataBinding event. System.Web.UI.WebControls.HyperLinkField does not
have a DataBinding event.
代码:
<asp:GridView ID="CustomersGridView" runat="server" AutoGenerateColumns="False">
<Columns>
<asp:BoundField DataField="FirstName" HeaderText="First Name" />
<asp:BoundField DataField="LastName" HeaderText="Last Name" />
<asp:HyperLinkField Text='<%# Eval("FirstName") %>' />
</Columns>
</asp:GridView>
答案 0 :(得分:3)
试试这个..
<asp:HyperLinkField
DataTextField="FirstName"
HeaderText="First Name"
SortExpression="FirstName"
DataNavigateUrlFields="FirstNameID"
DataNavigateUrlFormatString="PersonDetails.aspx?FirstNameID={0}" /> //use if you want to nevigate to other page
答案 1 :(得分:1)
<asp:HyperLinkField DataTextField="FirstName" />
答案 2 :(得分:1)
您需要将其转换为模板字段:
<asp:GridView ID="CustomersGridView" runat="server" AutoGenerateColumns="False">
<Columns>
<asp:BoundField DataField="FirstName" HeaderText="First Name" />
<asp:BoundField DataField="LastName" HeaderText="Last Name" />
<asp:TemplateField HeaderText="FirstName" SortExpression="FirstName">
<asp:itemtemplate>
<asp:HyperLinkField Text='<%# Eval("FirstName") %>' />
...