Question

在下面的代码中，我希望AdminDuration和BreakDuration根据UserID的值进行求和。目前我无法弄明白，并且它使用ReasonCode 7对所有持续时间的值求和。结果每个UserId都是相同的持续时间（不是我想要的！）。

Select SkillTargetID AS UserID,
(SELECT sum(Duration) 
   from [t_Agent_Event_Detail] 
   where ReasonCode = 7
   and DateTime > convert(DATETIME, '2013-01-31 08:00', 21)) as AdminDuration,
(SELECT sum(Duration) 
   from [t_Agent_Event_Detail] 
   where ReasonCode = 6
   and DateTime > convert(DATETIME, '2013-01-31 08:00', 21) 
   and SkillTargetID = [t_Agent_Event_Detail].SkillTargetID) as BreakDuration 
from [t_Agent_Event_Detail]
GROUP BY SkillTargetID

Answer 1

如果我理解正确，那应该是：

SELECT SkillTargetID AS UserID,
       sum(CASE WHEN ReasonCode = 7 THEN Duration ELSE 0 END) as AdminDuration,
       sum(CASE WHEN ReasonCode = 6 THEN Duration ELSE 0 END) as BreakDuration
FROM [t_Agent_Event_Detail]
WHERE DateTime > convert(DATETIME, '2013-01-31 08:00', 21)
GROUP BY SkillTargetID

如果基于另一列中的值，则求和

1 个答案: