lua重复/直到似乎使用原始值

Question

所以仍然致力于将数字转换为中文拼音的程序。完整的代码（请原谅不稳定，我非常感谢我的错误编码的所有帮助）

local digitmap = {
   ["0"] = "ying2",
   ["1"] = "yi1",
   ["2"] = "er2",
   ["3"] = "san1",
   ["4"] = "si4",
   ["5"] = "wu3",
   ["6"] = "liu4",
   ["7"] = "qi1",
   ["8"] = "ba1",
   ["9"] = "jiu3",
}

print("Enter a number to be converted (up to 10 digits long):")

while true do
    number = tonumber(io.read("*line"))
    nlength = #(tostring(number))
    if number ~= nil and nlength <= 10 then
        break
    end
    print("Invalid input or too long. Please try again:")
end

if number == 0 then
fconvnumber = "ying2"
zero = true
end

local cwords = {}
for c in string.gmatch(number, "%d") do
cwords[#cwords + 1] = digitmap[c]
end

if nlength == 2 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
elseif nlength == 3 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
elseif nlength == 4 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
elseif nlength == 5 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
elseif nlength == 6 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
elseif nlength == 7 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
    cwords[nlength - 6] = cwords[nlength - 6] .. " bai3 "
elseif nlength == 8 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
    cwords[nlength - 6] = cwords[nlength - 6] .. " bai3 "
    cwords[nlength - 7] = cwords[nlength - 7] .. " qian1 "
elseif nlength == 9 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
    cwords[nlength - 6] = cwords[nlength - 6] .. " bai3 "
    cwords[nlength - 7] = cwords[nlength - 7] .. " qian1 "
    cwords[nlength - 8] = cwords[nlength - 8] .. " yi4 "
elseif nlength == 10 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
    cwords[nlength - 6] = cwords[nlength - 6] .. " bai3 "
    cwords[nlength - 7] = cwords[nlength - 7] .. " qian1 "
    cwords[nlength - 8] = cwords[nlength - 8] .. " yi4 "
    cwords[nlength - 9] = cwords[nlength - 9] .. " shi2 "
end

while cwords[nlength] == "ying2" and zero ~= true do
    cwords[nlength] = nil
    nlength = nlength - 1
end

fconvnumber = table.concat(cwords)

fconvnumber = string.gsub(fconvnumber, "ying2 %a+%d", "ying2")
for i=1,nlength do
    fconvnumber = string.gsub(fconvnumber, "ying2 ying2", "ying2")
end
fconvnumber = string.gsub(fconvnumber, "yi1 shi2", "shi2")

print(fconvnumber)

所以，例如，如果我输入100，nlength是3，cwords [nlength] ==“ying2”，它会删除最后一个数组。但它不会再次循环并删除十位0.我知道我必须以某种方式忽略逻辑，但我只是没有看到它。直到使用nlength的早期valua？谢谢！

Answer 1

由于您没有提供完整的代码，因此很难说，但我怀疑您没有正确填充cwords，因为我没有在您发布的代码中看到问题。这对我有用：

cwords = {1, "ying2", "ying2"}
nlength = #cwords
print("started with", #cwords)
repeat
if cwords[nlength] == "ying2" then
    cwords[nlength] = nil
    nlength = nlength - 1
end
until cwords[nlength] ~= "ying2"
print("ended with", #cwords)

您可能希望将此更改为while循环，因为逻辑更简单：

while nlength > 0 and cwords[nlength] == "ying2" do
    cwords[nlength] = nil
    nlength = nlength - 1
end

Answer 2

逻辑没有错。 cwords或nlength未正确初始化。

但是，代码有点不稳定。你在每个循环中进行两次相同的测试，应该是a red flag。

你可以这样做：

while cwords[nlength] == "ying2" do
    cwords[nlength] = nil
    nlength = nlength - 1
end

或者像这样：

while cwords[#cwords] == "ying2" do
    table.remove(cwords)
end

但最有效的方法是在转换为拼音之前从源编号中删除尾随零：

while number % 10 == 0 do
    number = number / 10
end

或者：

strnumber = strnumber:match('(.-)0*$')

Answer 3

编辑：最后看，我帮你解决实际问题......

关于更新后代码的一些事项：

1）您在数字上使用gmatch，而不是字符串。

它只能因为强制而起作用，这不是一个好主意。您可以通过使用OO样式的调用来确保：

for c in number:gmatch("%d") do

它会破坏这个错误：

attempt to index global 'number' (a number value)

您应该保留该数字的字符串版本，如下所示：

while true do
    number = tonumber(io.read("*line"))
    str_number = tostring(number)
    nlength = #str_number
    if number ~= nil and nlength <= 10 then
        break
    end
    print("Invalid input or too long. Please try again:")
end

if number == 0 then
    fconvnumber = "ying2"
    zero = true
end

local cwords = {}
for c in str_number:gmatch("%d") do
    cwords[#cwords + 1] = digitmap[c]
end

2）这部分非常重复：

if nlength == 2 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
elseif nlength == 3 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
elseif nlength == 4 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
elseif nlength == 5 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
elseif nlength == 6 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
elseif nlength == 7 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
    cwords[nlength - 6] = cwords[nlength - 6] .. " bai3 "
elseif nlength == 8 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
    cwords[nlength - 6] = cwords[nlength - 6] .. " bai3 "
    cwords[nlength - 7] = cwords[nlength - 7] .. " qian1 "
elseif nlength == 9 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
    cwords[nlength - 6] = cwords[nlength - 6] .. " bai3 "
    cwords[nlength - 7] = cwords[nlength - 7] .. " qian1 "
    cwords[nlength - 8] = cwords[nlength - 8] .. " yi4 "
elseif nlength == 10 then
    cwords[nlength - 1] = cwords[nlength - 1] .. " shi2 "
    cwords[nlength - 2] = cwords[nlength - 2] .. " bai3 "
    cwords[nlength - 3] = cwords[nlength - 3] .. " qian1 "
    cwords[nlength - 4] = cwords[nlength - 4] .. " wan2 "
    cwords[nlength - 5] = cwords[nlength - 5] .. " shi2 "
    cwords[nlength - 6] = cwords[nlength - 6] .. " bai3 "
    cwords[nlength - 7] = cwords[nlength - 7] .. " qian1 "
    cwords[nlength - 8] = cwords[nlength - 8] .. " yi4 "
    cwords[nlength - 9] = cwords[nlength - 9] .. " shi2 "
end

您可以通过以下方式替换整个区块：

local suffixes = {"shi2","bai3","qian1","wan2","shi2","bai3","qian1","yi4","shi2"}
for i=1,nlength-1 do
    cwords[nlength - i] = string.format("%s %s ", cwords[nlength - i], suffixes[i])
end

3）这没用：

if number == 0 then
    fconvnumber = "ying2"
    zero = true
end

你设置fconvnumber但是你会在以后的行中重新设置它：

fconvnumber = table.concat(cwords)

零测试仅在while循环中使用一次：

while cwords[nlength] == "ying2" and zero ~= true do
    cwords[nlength] = nil
    nlength = nlength - 1
end

此外，您每次迭代都会重复测试。您可以删除第一个块并写入：

if number ~= 0 then
    while cwords[nlength] == "ying2" do
        cwords[nlength] = nil
        nlength = nlength - 1
    end
end

最终您的重构代码如下所示：

local digitmap = {
    ["0"] = "ying2",
    ["1"] = "yi1",
    ["2"] = "er2",
    ["3"] = "san1",
    ["4"] = "si4",
    ["5"] = "wu3",
    ["6"] = "liu4",
    ["7"] = "qi1",
    ["8"] = "ba1",
    ["9"] = "jiu3",
}

print("Enter a number to be converted (up to 10 digits long):")

while true do
    number = tonumber(io.read("*line"))
    str_number = tostring(number)
    nlength = #str_number
    if number ~= nil and nlength <= 10 then
        break
    end
    print("Invalid input or too long. Please try again:")
end

local cwords = {}
for c in str_number:gmatch("%d") do
    cwords[#cwords + 1] = digitmap[c]
end

local suffixes = {"shi2","bai3","qian1","wan2","shi2","bai3","qian1","yi4","shi2"}
for i=1,nlength-1 do
    cwords[nlength - i] = string.format("%s %s ", cwords[nlength - i], suffixes[i])
end

if number ~= 0 then
    while cwords[nlength] == "ying2" do
        cwords[nlength] = nil
        nlength = nlength - 1
    end
end

fconvnumber = table.concat(cwords)

fconvnumber = string.gsub(fconvnumber, "ying2 %a+%d", "ying2")
for i=1,nlength do
    fconvnumber = string.gsub(fconvnumber, "ying2 ying2", "ying2")
end
fconvnumber = string.gsub(fconvnumber, "yi1 shi2", "shi2")

print(fconvnumber)

可能仍有一些事情可以改进，但这已经很简单了：）

现在让我们解决真正的问题！

你说：

  

所以，例如，如果我输入100，nlength是3，cwords [nlength] ==   “ying2”，它删除最后一个数组。但它并没有循环   再次删除十位0.我知道我必须错过逻辑   不知何故，但我只是没有看到它。

那是因为第一次迭代后数组的最后一个元素不是“ying2”，而是“ying2 shi2”！想一想，你早些时候已经联系了“shi2”。

现在的问题是：你期待的结果是“yi1 bai3”还是“yi1”？

如果是“yi1”，只需在连接之前消除零。如果是“yi1 bai3”，请执行以下操作：

local suffixes = {"shi2","bai3","qian1","wan2","shi2","bai3","qian1","yi4","shi2"}
cwords[nlength] = {cwords[nlength]}
for i=1,nlength-1 do
    cwords[nlength - i] = {cwords[nlength - i],string.format(" %s ",suffixes[i])}
end

if number ~= 0 then
    while cwords[nlength][1] == "ying2" do
        cwords[nlength] = nil
        nlength = nlength - 1
    end
end

for i=1,nlength do
    cwords[i] = table.concat(cwords[i])
end

fconvnumber = table.concat(cwords)