Question

如何在DOS提示符下计算脚本？

* NIX等效物将是：

$ time myscript

real 0m0.886s
user 0m0.846s
sys 0m0.031s

$

是否有相当于DOS的DOS？感谢

Answer 1

您可以将其放在批次的开头和结尾：

echo %time%

Answer 2

您可以使用Windows Server 2003 Resource Kit中的timeit.exe。您还可以获得大量其他有用的工具和Unix命令端口。

C:\Documents and Settings\Rob>timeit sleep 3

Version Number:   Windows NT 5.1 (Build 2600)
Exit Time:        2:40 pm, Thursday, December 10 2009
Elapsed Time:     0:00:03.296
Process Time:     0:00:00.015
System Calls:     7576
Context Switches: 1974
Page Faults:      1072
Bytes Read:       6172
Bytes Written:    11086
Bytes Other:      144432

Answer 3

这是一个DOS批处理脚本，它将为您计算时差，而不仅仅是echo %time%。

只要您的“定时用户部分”运行时间不超过24小时，以下代码就可以正常运行。请原谅或给我建议，这是我正在进行的工作，我花了大约一个小时。

将“PAUSE”替换为对脚本的调用以计算自己的代码。

DOS BAT文件跟进：

注意：编辑修复了前导零为八进制而不是十进制的问题。

注意：已经过编辑以处理“午夜”小时环绕运行并将前导零置于输出中。

@echo off
@rem --------------------------------------------
setlocal ENABLEEXTENSIONS

set start_time=%time%
echo Beginning at: %start_time%
echo Running Timed Batch File
echo.

@rem echo %*  <-- Extension for all args -- easier than following line
@rem echo %0 %1 %2 %3 %4 %5 %6 %7 %8 %9 ... ...

@rem DO YOUR WORK HERE -- see "call" / PAUSE is here to "fake" work
@rem call userscript.bat %*
PAUSE

set stop_time=%time%
echo.
echo Timed Batch File Completed
echo Start time: %start_time%
echo Stop time : %stop_time%


set TEMPRESULT=%start_time:~0,2%
call:FN_REMOVELEADINGZEROS
set start_hour=%TEMPRESULT%
@rem
set TEMPRESULT=%start_time:~3,2%
call:FN_REMOVELEADINGZEROS
set start_min=%TEMPRESULT%
@rem
set TEMPRESULT=%start_time:~6,2%
call:FN_REMOVELEADINGZEROS
set start_sec=%TEMPRESULT%
@rem
set TEMPRESULT=%start_time:~9,2%
call:FN_REMOVELEADINGZEROS
set start_hundredths=%TEMPRESULT%

set TEMPRESULT=%stop_time:~0,2%
call:FN_REMOVELEADINGZEROS
set stop_hour=%TEMPRESULT%
@rem
set TEMPRESULT=%stop_time:~3,2%
call:FN_REMOVELEADINGZEROS
set stop_min=%TEMPRESULT%
@rem
set TEMPRESULT=%stop_time:~6,2%
call:FN_REMOVELEADINGZEROS
set stop_sec=%TEMPRESULT%
@rem
set TEMPRESULT=%stop_time:~9,2%
call:FN_REMOVELEADINGZEROS
set stop_hundredths=%TEMPRESULT%

set /A start_total=(((((%start_hour%*60)+%start_min%)*60)+%start_sec%)*100)+%start_hundredths%
set /A stop_total=(((((%stop_hour%*60)+%stop_min%)*60)+%stop_sec%)*100)+%stop_hundredths%

set /A total_time=%stop_total% - %start_total%

set /A total_hundredths=%total_time% %% 100
set total_hundredths=00%total_hundredths%
set total_hundredths=%total_hundredths:~-2%
set /A total_time=%total_time% / 100

set /A total_sec="%total_time% %% 60"
set total_sec=00%total_sec%
set total_sec=%total_sec:~-2%
set /A total_time=%total_time% / 60

set /A total_min="%total_time% %% 60"
set total_min=00%total_min%
set total_min=%total_min:~-2%
set /A total_time=%total_time% / 60

set /A total_hour="%total_time% %% 60"
@rem Handle if it wrapped around over midnight
if "%total_hour:~0,1%"=="-" set /A total_hour=%total_hour% + 24

echo Total time: %total_hour%:%total_min%:%total_sec%.%total_hundredths%

@rem --------------------------------------------
@rem Exit the BAT Program
endlocal
goto END

@rem --------------------------------------------
@rem FN_REMOVELEADINGZEROS function
@rem  Used to remove leading zeros from Decimal
@rem  numbers so they are not treated as Octal.
:FN_REMOVELEADINGZEROS
if "%TEMPRESULT%"=="0" goto END
if "%TEMPRESULT:~0,1%" NEQ "0" goto END
set TEMPRESULT=%TEMPRESULT:~1%
goto FN_REMOVELEADINGZEROS

@rem --------------------------------------------
@rem BAT PROGRAM / FUNCTION FILE EXIT
:END

Answer 4

如果您不介意使用第三方EXE寻求帮助，timer.exe中的Gammadyne非常有用。

setlocal ENABLEEXTENSIONS
FOR /F %%G IN ('timer') DO SET start_time=%%G

@rem Do your work Here
call userscript.bat %*

timer %start_time% "Total time"
endlocal

如何在DOS下计算脚本？

4 个答案: