说我有:
IList<Person> people = new List<Person>();
person对象具有FirstName,LastName和Gender等属性。
如何将其转换为Person对象的属性列表。例如,到名字列表。
IList<string> firstNames = ???
答案 0 :(得分:138)
List<string> firstNames = people.Select(person => person.FirstName).ToList();
并进行排序
List<string> orderedNames = people.Select(person => person.FirstName).OrderBy(name => name).ToList();
答案 1 :(得分:4)
IList<string> firstNames = (from person in people select person.FirstName).ToList();
或者
IList<string> firstNames = people.Select(person => person.FirstName).ToList();
答案 2 :(得分:3)
firstNames = (from p in people select p=>p.firstName).ToList();
答案 3 :(得分:1)
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
namespace TestProject
{
public partial class WebForm3 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
SampleDataContext context = new SampleDataContext();
List<Employee> l = new List<Employee>();
var qry = from a in context.tbl_employees where a.Gender=="Female"
orderby a.Salary ascending
select new Employee() {
ID=a.Id,
Fname=a.FName,
Lname=a.Lname,
Gender=a.Gender,
Salary=a.Salary,
DepartmentId=a.DeparmentId
};
l= qry.ToList();
var e1 = from emp in context.tbl_employees
where emp.Gender == "Male"
orderby emp.Salary descending
select emp;
GridView1.DataSource = l;
GridView1.DataBind();
}
}
public class Employee
{
public Int64 ID { get; set; }
public String Fname { get; set; }
public String Lname { get; set; }
public String Gender { get; set; }
public decimal? Salary { get; set; }
public int? DepartmentId { get; set; }
}
}
答案 4 :(得分:0)
using System.Collections.Generic;
using System.Linq;
IList<Person> people = new List<Person>();
IList<string> firstNames = people.Select(person => person.FirstName).ToList();
答案 5 :(得分:-2)
这会将它变成一个列表:
List<string> firstNames = people.Select(person => person.FirstName).ToList();
这将返回一个(第一个):
var firstname = people.select(e => e.firstname).FirstOrDefault();