Question

我在SQL Server 2005中有像Rep_table，Selling，Upgrade和Delivery这样的表。

我正在尝试获得销售，升级和交付中的列数总和。 Rep_Table具有Rep_TableID，CommID和MerchantID列。销售有SellingID，Rep_TableID，AmountSold，S_AmountCollected，升级包含UpgradingID，Rep_TableID，AmountUpgraded，U_AmountCollected列交货有列DeliveryID，Rep_TableID，D_AmountCollected

Rep_Table将有3条记录，每条记录用于销售，升级和交付。我的目标是获得已售出和升级的总和，从3张桌子和余额中收集的所有金额。

当我尝试以下查询时，我不会看到联接运作良好。此查询为我提供了1行销售，1行升级信息和每个商家的另一行交付。我正在寻找的是所有的计算都应该完成，每个商家都要排成一列。我希望我清楚地知道我在问什么。谢谢大家！

Select *, isnull(cast(S.AmountSold as numeric(10,2)), 0) + isnull(cast(U.AmountUpgraded as numeric(10,2)), 0) as AmountSold,
isnull(cast(S.S_AmountCollected as numeric(10,2)), 0) + isnull(cast(U.U_AmountCollected as numeric(10,2)), 0) + isnull(cast(D.D_AmountCollected as numeric(10,2)), 0) as AmountCollected,
(isnull(cast(S.AmountSold as numeric(10,2)), 0) + isnull(cast(U.AmountUpgraded as numeric(10,2)), 0)) - 
(isnull(cast(S.S_AmountCollected as numeric(10,2)), 0) + isnull(cast(U.U_AmountCollected as numeric(10,2)), 0) + + isnull(cast(D.D_AmountCollected as numeric(10,2)), 0) ) as Balance

 from Rep_Table RD
inner join Merchant M on M.MerchantID = RD.MerchantID --for MerchantInfo
left outer join SellingInfo S on S.RepInfoID = RD.RepInfoID
left outer join UpgradingInfo U on U.RepInfoID = RD.RepInfoID
left outer join DeliveryInfo D on D.RepInfoID = RD.RepInfoID
where RD.CommuniTeeID = @CommuniTeeID

Answer 1

好的，给下面一个镜头：

Select sum(isnull(cast(S.AmountSold as numeric(10,2)), 0) + isnull(cast(U.AmountUpgraded as numeric(10,2)), 0)) as AmountSold
    , sum(isnull(cast(S.S_AmountCollected as numeric(10,2)), 0) + isnull(cast(U.U_AmountCollected as numeric(10,2)), 0) + isnull(cast(D.D_AmountCollected as numeric(10,2)), 0)) as AmountCollected
    , sum((isnull(cast(S.AmountSold as numeric(10,2)), 0) + isnull(cast(U.AmountUpgraded as numeric(10,2)), 0)) - (isnull(cast(S.S_AmountCollected as numeric(10,2)), 0) + isnull(cast(U.U_AmountCollected as numeric(10,2)), 0) + + isnull(cast(D.D_AmountCollected as numeric(10,2)), 0) )) as Balance
from Rep_Table RD
inner join Merchant M on M.MerchantID = RD.MerchantID --for MerchantInfo
left outer join SellingInfo S on S.RepInfoID = RD.RepInfoID
left outer join UpgradingInfo U on U.RepInfoID = RD.RepInfoID
left outer join DeliveryInfo D on D.RepInfoID = RD.RepInfoID
where RD.CommuniTeeID = @CommuniTeeID
group by m.MerchantID

我在每个列中添加了SUM（我删除了*，因为它可能使事情变得复杂）我在GROUP BY上添加了m.MerchantID。

SQL中3个不同表的列总和

1 个答案: