我在python3中编写脚本,但我无法解决以下问题。
我有一个这种模式的名单列表:
ZINC123456
ZINC234567
ZINC345678
ZINC456789
...
我有一个像这样的大文件:
ZINC123456
xxx
xxx
xxx
ZINC987654
xxy
xxy
xxy
xxy
ZINC654987
...
我想做的是: 循环遍历第一个列表中的每个项目并在第二个文件中搜索它。找到此项目时,请复制此行以及以下所有内容,直到下一个ZINCxxxxxx模式到达新文件。
我该怎么做?非常感谢你的帮助!
编辑:感谢Sudipta Chatterjee,我找到了以下解决方案:
import sys
finZ=open(sys.argv[1],'r')
finX=open('zinc.sdf','r')
fout=open(sys.argv[1][:7]+'.sdf','w')
list=[]
thislinehaszinc = False
zincmatching = False
for zline in finZ:
if zline[0:4] == "ZINC":
name = zline[:-1] #line[4:-1]
if name not in list:
list.append(name)
for xline in finX:
if xline[0:4] == "ZINC":
thislinehaszinc = True
zincmatching = False
for line in list:
if line == xline[:-1]:
zincmatching = True
fout.write(xline)
print('Found: '+xline)
pass
else:
pass
else:
thislinehaszinc = False
if thislinehaszinc == False and zincmatching == True:
fout.write(xline)
答案 0 :(得分:-1)
# Clarified from comments - the program is to act as a filter so that any lines
# which have a pattern 'ZINC' in the second file but do not belong in the first
# should stop the dump until the next matching zinc is found
fileZ = open ('file_with_zinc_only.txt', 'r').readlines()
fileX = open ('file_with_x_info.txt', 'r').readlines()
fileOutput = open ('file_for_output.txt', 'w')
thisLineHasZinc = False
zincMatching = False
for xline in fileX:
#print "Dealing with", xline
if len(xline.split('ZINC')) != 1:
thisLineHasZinc = True
zincMatching = False
for zline in fileZ:
#print "Trying to match",zline
if zline == xline:
#print "************MATCH***************"
zincMatching = True
fileOutput.write (zline)
#print "**",xline
break
else:
thisLineHasZinc = False
# If we are currently under a block where we've found a ZINC previously
# but not yet reached another ZINC line, write to file
#print 'thisLineHasZinc',thisLineHasZinc,'zincMatching',zincMatching
if thisLineHasZinc == False and zincMatching == True:
fileOutput.write (xline)
#print "**** "+ xline
fileOutput.close()