我在这里要做的是使用xml数据向Rest Web服务发出请求。
这就是我现在所拥有但我不确定如何传递我的xml数据
XElement xml = new XElement("MatchedOptions",
from m in _matchedOptionsList
select new XElement("Listing",
new XElement("DomainID", _trafficCopInputs.DomainID),
new XElement("AdSource", _trafficCopInputs.AdSource),
new XElement("Campaign", _trafficCopInputs.Campaign),
new XElement("AdGroup", _trafficCopInputs.AdGroup),
new XElement("RedirectURL", m.RedirectPath),
new XElement("FunnelKeyword", m.FunnelKeyword)));
HttpWebRequest req = WebRequest.Create("http://something.com/")
as HttpWebRequest;
req.Method = "POST";
req.ContentType = "text/xml";
req.ContentLength = 0;
StreamWriter writer = new StreamWriter(req.GetRequestStream());
writer.WriteLine(xml.ToString());
答案 0 :(得分:6)
我使用WebClient类:
WebClient webClient = new WebClient();
using (webClient)
{
requestInterceptor.OnRequest(webClient);
var enc = new ASCIIEncoding();
return enc.GetString(webClient.UploadData(uri, enc.GetBytes(dataAsString)));
}
答案 1 :(得分:5)
您正在做的事情没有根本错误,但您需要刷新/关闭请求流编写器。这可以通过using
构造轻松完成,因为处理编写器也会刷新它:
using (StreamWriter writer = new StreamWriter(req.GetRequestStream()))
{
writer.WriteLine(xml.ToString());
}
然后,您需要调用GetResponse
来实际执行请求:
req.GetResponse()
(请注意,从此返回的HttpWebResponse
也是一次性的,所以不要忘记处置它。)